Answer:
32centimeters
Step-by-step explanation:
4 sides are in a sqaure and all of them are equal so
8 times 4 is 32
First let's get the equation 2x - y = -4 into slope intercept form. To do this first subtract 2x to both sides:
2x - 2x - y = -4 - 2x
0 - y = -4 - 2x
-y = -4 - 2x
Y still isn't completely isolated, it still has the negative attached to it. To get rid of the negative divide both sides by -1
-y / -1 = (-4 - 2x) / -1
y = 4 + 2x
y = 2x + 4
slope intercept formula is:
y = mx + b
m is the slope
b is the y-intercept
For a line that is parallel to y = 2x + 4 and passes through point (2, 5) you will need to have the same slope (2)
This is the formula we know so far for the line parallel to y = 2x + 4:
y = 2x + b
Now we must find b
To do that you must plug in the point the line goes through ( 2, 5) in the x and y of the equation.
5 = 2(2) + b
5 = 4 + b
Now solve for b by subtracting 4 to both sides
1 = b
y = 2x + 1
^^^This line is parallel to 2x - y = -4 and goes through the point (2, 5)
Hope this helped!
~Just a girl in love with Shawn Mendes
If the length of rectangular school hall is 4 times the width and the perimeter be 55m, then the length is 22m and the width of the school hall be 5.5m.
Given that the length of rectangular school hall is 4 times the width.
We are required to find the length and breadth of the rectangle which has the length be 4 times the width.
Perimeter of rectangle is the sum of all the length and breadth of that rectangles.
Perimeter of rectangle is given as 55m
Perimeter=2(L+B)
let the width of rectangle be x.
Length of that rectangle be 4x.
According to question,
2(x+4x)=55
2*5x=55
10x=55
x=55/10
x=5.5 m
Width be 5.5 m.
Length of rectangle be 4*5.5=22m.
Hence if the length of rectangular school hall is 4 times the width then the length is 22m and the width of the school hall be 5.5m.
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