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CaHeK987 [17]
3 years ago
15

Equivalent expression to 3(4m-2)-2(m+5

Mathematics
1 answer:
wolverine [178]3 years ago
4 0

Answer:

10m - 16

Step-by-step explanation:

1.  Perform the indicated multiplication.  We get 12m - 6 - 2m - 10.

2.  Combine like terms:  We get 10m - 16

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(12 divided by 3) 2 – (18 divided by 3 2)) < (4 divided by 2)
gladu [14]

Answer:

(12 \div 3)(2 - (18 \div 32) \\  = 4(2 -  \frac{19}{16} ) \\  = 4( \frac{23}{16} ) \\  =  \frac{23}{4}  \\ since \: (4 \div 2) = 2 \\  \frac{23}{4} is \: not \:  < 2 \: but \: its \:  > 2

4 0
3 years ago
The equation of the line through point (-5,0) and parallel to the y-axis is
Mrac [35]
It's x=-5. It is a vertical line, and vertical lines have a consistent x coordinate. Since it passes through (-5,0), you take the x-coordinate of this point.
4 0
3 years ago
HELP PLEASE&lt;3 <br> Find the missing angle <br> Btw its trigonometry
ira [324]

Answer:

x = 16.6

Step-by-step explanation:

Since we know the measure of an acute angle (31 degrees) of a right angle triangle, and of the side opposite to the angle (10), and we need to find the measure of the adjacent side "x", we use the tangent function:

tan(\theta) = \frac{opposite}{adjacent} \\tan(31^o)=\frac{10}{x}\\x=\frac{10}{tan(31^o)} \\x \approx 16.64279

which rounded to one decimal is

x = 16.6

6 0
3 years ago
Simplify The following equations
Y_Kistochka [10]
<span>mostly collect like terms
use associative property which is
(a+b)+c=a+(b+c)
also -a+b-c=(-a)+(b)+(-c) so you can move them around
and remember that:
you just use a general rule
x+x=2x
x^2+x^2=2x^2
3xy4xy=7xy
3x+4x^2=3x+4x^2
you can only add like terms( like terms are terms that are same name like x or y are differnt, and like terms have same power exg x^2 and x^3 and x^1/2 and such

I will oly put the naswers because I don't have much time

first one: 2a+3b+2c

second one: remember that -(-6c)=+6c so the answer is c-10a-2b

third one: -a-8b-5c
</span>
3 0
3 years ago
why write a quadratic function whose graph has the given characteristics vertex :(2,3) point on graph (0,-1)
GaryK [48]
<h3>Answer:</h3>

f(x) = -(x -2)² +3

<h3>Step-by-step explanation:</h3>

We can fill in the vertex (h, k) values immediately in the vertex form ...

... f(x) = a(x -h)² +k

To find the value of a, we solve the equation for a at some point other than the vertex. The given point is (0, -1), so we can use that:

... -1 = a(0 -2)² +3

... -4 = 4a . . . . . . . . . subtract 3, simplify

... -1 = a . . . . . . . . . . . divide by 4

Now, we know the function is ...

... f(x) = -(x -2)² +3

5 0
3 years ago
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