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CaHeK987 [17]
3 years ago
15

Equivalent expression to 3(4m-2)-2(m+5

Mathematics
1 answer:
wolverine [178]3 years ago
4 0

Answer:

10m - 16

Step-by-step explanation:

1.  Perform the indicated multiplication.  We get 12m - 6 - 2m - 10.

2.  Combine like terms:  We get 10m - 16

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Find the value of f (6)
Natali5045456 [20]
Answer: 6f

Explanation: Move 6 to the left of F and remove the parentheses
5 0
2 years ago
Norma has an A-frame cabin.The back is shown below. How many square feet of paint will she need to cover the back of the cabin?
a_sh-v [17]
I FOUND YOUR FULL QUESTION IN OTHER FUENETES.
 PLEASE SEE ATTACHED IMAGE. 
 For this case what you should do is find the area of the triangle which will be given by:
 A = (1/2) * (b) * (h)
 Where
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 h: height
 Substituting the values we have:
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7 0
3 years ago
Given m ||n, find the value of x <br> 167°
frutty [35]

Answer:

13

Step-by-step explanation:

180-167= 13

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7 0
2 years ago
Does anyone know how to do this?
Strike441 [17]

Answer:

196 m^{2}

Step-by-step explanation:

A square is a  <u>shape that which all sides are equal</u>

<em>14 is one side of the square and to find the area of a square/rectangle, you do  </em><u><em>length*width </em></u>

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6 0
2 years ago
Show that the relation R consisting of all pairs(x, y)such that x and y are bit strings of length three or more that agree in th
Mice21 [21]

Answer:

See proof below

Step-by-step explanation:

An equivalence relation R satisfies

  • Reflexivity: for all x on the underlying set in which R is defined, (x,x)∈R, or xRx.
  • Symmetry: For all x,y, if xRy then yRx.
  • Transitivity: For all x,y,z, If xRy and yRz then xRz.

Let's check these properties: Let x,y,z be bit strings of length three or more

The first 3 bits of x are, of course, the same 3 bits of x, hence xRx.

If xRy, then then the 1st, 2nd and 3rd bits of x are the 1st, 2nd and 3rd bits of y respectively. Then y agrees with x on its first third bits (by symmetry of equality), hence yRx.

If xRy and yRz, x agrees with y on its first 3 bits and y agrees with z in its first 3 bits. Therefore x agrees with z in its first 3 bits (by transitivity of equality), hence xRz.

5 0
3 years ago
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