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Ivenika [448]
3 years ago
14

10х5 + 5x3 — 14x2 – 7

Mathematics
2 answers:
NeTakaya3 years ago
7 0
If we use PEMDAS (parenthesis,exponents,multiplication,division,addition, subtraction) we should multiply first so the equation 10x5+5x3-14x2-7 would convert to 50+15-28-7 then we add the like terms and get 65-21 which is 44
marishachu [46]3 years ago
4 0
The answer to your question should be 116
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BabaBlast [244]

Answer:

3x-12=y

which equals to

1/y=1/(3x-12)

Now,multiply both sides by x

x/y=x/(3x-12)

8x/2y=4x/y=4x/(3x-12)

Step-by-step explanation:

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5 0
3 years ago
In the basketboll gome yesterday. Brionna
Talja [164]
She would make 7 of her shots shooting or 7/20 percent which is 35% shooting. You can also multiply 20x0.35 and it will give you 7.
6 0
3 years ago
Guys I really need help with these too thanks u before!!!!
Natali5045456 [20]
Hey!!

here is your answer >>>

1) 3x - 10 > 11

let's take this as 3x - 10 = 11

3x = 21

x = 7
So, The numbers of X are always more than 7

2) 9x + 2 < 5

9x + 2 = 5

9x = 3

x = 1÷2

The numbers of X are always less than 1 ÷ 2

3) 2x + 8 < 6

2x + 8 = 6

2x = 2

x = 1

The numbers of X are less than 1

4) 4x - 3 < 12

4x - 3 = 12

4x = 15

x = 15 ÷ 4

The numbers of X are less than 15 ÷ 4

5) 2 ( 9 + x ) > 20

2 ( 9 + x ) = 20

9 + x = 10

x = 1

The numbers of X are more than 1

We can solve the rest using this

Hope my answer helps!
5 0
3 years ago
PLEASE HELP!!!!!<br> will mark brainliest!!!!!
Nataly [62]

Answer:

x. f(×)

6. 9

7. 7

8. 5

9. 3

10. 1

6 0
2 years ago
Which of the following is equivalent to the expression below sqrt 8 - sqrt 72 + sqrt 50
mash [69]

Answer:

Step-by-step explanation:

\sqrt{8}-\sqrt{72}+\sqrt{50} These cannot combine the way they are. The rule for adding and subtracting radicals is really picky. Not only does the index have to be the same (the little number that is sitting outside in the bend of the radical {ours is a 2, which isn't usually there, but is instead understood to be a square root}), but the radicand, the expression under the square root (or cubed root, or fourth root, etc) has to the same as well. All of our radicals are square roots, so that's good, but the radicands are all different. The first one is an 8, the next one is a 72, and the last one is a 50. BUT if we can rewrite them by simplifying them and then the radicands are the same, we're in good shape.

Simplify by taking the prime factorization of each of those numbers.

8: 4*2 and 4 is a perfect square, so we'll stop there

72: 36*2 and 36 is a perfect square, so we'll stop there

50: 25*2 and 25 is a perfect square, so we'll stop there.

Now, rewrite each one of them in terms of their prime factorization:

\sqrt{4*2}-\sqrt{36*2}+\sqrt{25*2} and then pull out each perfect square as its root:

2\sqrt{2}-6\sqrt{2}+5\sqrt{2} and now all the radicands are the same, so we can add them to get

1\sqrt{2}  or simply  \sqrt{2}

6 0
2 years ago
Read 2 more answers
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