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cupoosta [38]
3 years ago
15

If the area of a rectangular garden is 12x2−20x. What is the length if the width is 4x? 8x2−168 x squared minus 16 3x2−5x3 x squ

ared minus 5 x 8x−168 x minus 16 3x−5
Mathematics
1 answer:
krok68 [10]3 years ago
5 0

Answer:

3x - 5

Step-by-step explanation:

If the area of a rectangular garden is 12x²−20x. What is the length if the width is 4x?

The formula for the Area of a rectangular shape = Length × Width

Area = 12x² - 20x

Length = 4x

Width = Area/Length

Width = 12x² - 20x/4x

Width = 12x²/4x - 20x/4x

Width = 3x - 5

The width of the Rectangular shape = 3x - 5

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A rectangular block measures 3 cm x 4 cm x 3 cm how much water would it displace?
nika2105 [10]

Answer:

36c^3m^3x^2

Step-by-step explanation:

  1. you first multiply 3 cm by 4 cm by 3 cm to get 36 cm.
  2. its mass in air and its effective mass when submerged in water (density = 1 gram per cubic centimeter).
  3. 1.0 g/cm3
  4. then you get the answer 36c^3m^3x^2
4 0
3 years ago
Please answer fast ASAP I give brainliest
ddd [48]

Answer:

7 seconds

Step-by-step explanation:

y=-16t²+96t+112, where t is time and y is distance above water.

We are looking for t when y=0

-16t²+96t+112=0

t²-6t-7=0

(t-7)(t+1)=0

Either t=7 or t=-1.

Since we cant have negative time, the answer is t=7

3 0
3 years ago
The model below represents an equation. Which value of x makes the equation<br> true?
Sliva [168]

Answer:

1,1,1,1

Step-by-step explanation:

I believe this is right

3 0
2 years ago
to make 3 dozen cookies, 1 1/4 cups of pecan halves are required. how many dozen cookies can be made with 5 cups of pecan halves
In-s [12.5K]

Answer:

12 dozen

Step-by-step explanation:

create a proportion of: dozen cookies / cups of pecan

let 'd' = dozen cookies

(3/1 ÷ 5/4) = (d ÷ 5)

simplify 3/1 ÷ 5/4 to be:  3/1 x 4/5, which equals 12/5

12/5 = d/5

cross-multiply to get:

5d = 60

d = 12

6 0
2 years ago
may someone help me ASAP? I am solving polynomial equations and I don't know how to do it, here is the equation... x^4+11x^2=3x^
koban [17]

<u>Answer:</u>

x=2\sqrt{2}, x=-2\sqrt{2}, x=4i, x=-4i

<u>Step-by-step explanation:</u>

x^4+11x^2=3x^2+128

First, we subtract 128 from both sides:

x^4+11x^2-128=3x^2

Then, we subtract 3x^2 from both sides:

x^4+8x^2-128=0

Rewrite the equation:

u^2+8u-128=0

Insert and solve:

u^2+8u-128=0\\u=8,u=-16\\x^2=8:x=2\sqrt{2},x= -2\sqrt{2} \\x^2=-16:x=4i,x=-4i

<em>Please give Brainliest</em>

8 0
3 years ago
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