Given a right triangle with base, b and height, h with the angle opposide side h as θ.
The area of a triangle is given by
![A= \frac{1}{2} bh](https://tex.z-dn.net/?f=A%3D%20%5Cfrac%7B1%7D%7B2%7D%20bh)
But,
![\tan\theta= \frac{h}{b} \\ \\ \Rightarrow h=b\tan\theta](https://tex.z-dn.net/?f=%5Ctan%5Ctheta%3D%20%5Cfrac%7Bh%7D%7Bb%7D%20%20%5C%5C%20%20%5C%5C%20%5CRightarrow%20h%3Db%5Ctan%5Ctheta)
Therefore, the area of the triangle in terms of <span>b and θ only is given by
![A= \frac{1}{2} b(b\tan\theta)= \frac{1}{2} b^2\tan\theta](https://tex.z-dn.net/?f=A%3D%20%5Cfrac%7B1%7D%7B2%7D%20b%28b%5Ctan%5Ctheta%29%3D%20%5Cfrac%7B1%7D%7B2%7D%20b%5E2%5Ctan%5Ctheta)
</span>
Given that there are 12 persons, the first choice may be in 12 different ways, the second choice may be in 11 different ways, ther third in 10 different ways, the fourth in 9 different ways and the fith in 8 different ways, for a total of:
12x11x10x9x8 different combinations.
Now you have to take in account that 5x4x3x2 are repetitions. So you have to divide the previos counting by 5x4x3x2.
(12x11x10x9x8)/(5x4x3x2) = 792 different subcommittees.
Also, you can use the formula for combinations: C(m,n) = m! / (n! (m-n)!)
C (12, 5) = 12! / (5!) (12-5)! = [12x11x10x9x8x7!] / [5! 7!] = [12x11x10x9x8]/[5x4x3x2] = 792
<h3>
Answer: addition property of inequality</h3>
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Explanation:
These are the steps to focus on
step 3: -6x - 8 < -2
step 4: -6x < 6
The move from the third step to the fourth step has us adding 8 to both sides. Therefore, we use the addition property of inequality.
That property has four forms
- If
then ![a + c > b+c](https://tex.z-dn.net/?f=a%20%2B%20c%20%3E%20b%2Bc)
- If
then ![a+c < b+c](https://tex.z-dn.net/?f=a%2Bc%20%3C%20b%2Bc)
- If
then ![a + c \ge b+c](https://tex.z-dn.net/?f=a%20%2B%20c%20%5Cge%20b%2Bc)
- If
then ![a+c \le b+c](https://tex.z-dn.net/?f=a%2Bc%20%5Cle%20b%2Bc)
It's similar to the idea of starting with a = b, then adding c to both sides to get a+c = b+c
We add the same thing to both sides to keep things balanced.
Apparently, the calculator at the link in your lesson is fully capable of giving you the necessary numbers. My own TI-84 work-alike gives me the account balances, but the rest of the numbers need to be figured.
In 30 years, there are 12×30 = 360 months, or 4×30 = 120 quarters. See the calculator results below. Your table can be filled in using the given information to find the contribution amount. The calculator gives the final balance. The interest amount is found by subtracting the contribution amount from the final balance.
![\begin{array}{cccc}\text{Opt}&\text{Contributions}&\text{Int}&\text{Final Bal}\\1&360\cdot 25=9000&6250.50&15250.50\\2&120\cdot 75=9000&8467.04&17467.04\\3&1000&5489.17&6489.17\end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bcccc%7D%5Ctext%7BOpt%7D%26%5Ctext%7BContributions%7D%26%5Ctext%7BInt%7D%26%5Ctext%7BFinal%20Bal%7D%5C%5C1%26360%5Ccdot%2025%3D9000%266250.50%2615250.50%5C%5C2%26120%5Ccdot%2075%3D9000%268467.04%2617467.04%5C%5C3%261000%265489.17%266489.17%5Cend%7Barray%7D)