Can i have an equation pls

Work Out The Area Of The Shape: (Picture is shown in attachment)

Elenna [48]

Answer:

<h2>Solution :-</h2>

The given shape is known as Trapezium or Trapezoid.

Area of trapezium = ½(Sum of parallel dides) × Height

Area = ½ (3 + 6) × 4

Area = (3 + 6) × 2

Area = 9 × 2

Area = 18 m²

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7 0

2 years ago

What is 6÷2 squaredwhat is 6 ÷ 2 squared

slamgirl [31]

Answer:

(6/2)² = 3² = 9

6²/2² = 36/4 = 9

5 0

2 years ago

Read 2 more answers

Log based question, i just need help with parts b and c

Tanya [424]

Answer:

b) There is translation 3 units to the right and 1 unit up

c) The domain is {x I x > 3}

The equation of the asymptote is x = 3

Step-by-step explanation:

* Lets revise the rule of the translation

- If the function f(x) translated horizontally to the right

by h units, then the new function g(x) = f(x - h)

- If the function f(x) translated horizontally to the left

by h units, then the new function g(x) = f(x + h)

- If the function f(x) translated vertically up

by k units, then the new function g(x) = f(x) + k

- If the function f(x) translated vertically down

by k units, then the new function g(x) = f(x) – k

* Now lets solve the problem

b) ∵ f(x) = $log_{2} (x-3)+1$

∵ The parent function is $log_{2} x$

∴ x is changed to (x - 3), that means there is a translation 3 units

to the right

∵ We add the parent function by 1, that means there is a translation

1 unit up

* There is translation 3 units to the right and 1 unit up

c) To find the domain of the function, find the values of x which

make the function undefined

∵ $log_{2}(0)$ is undefined

∴ x - 3 can not be 0

∵ x - 3 = 0 ⇒ add 3 to both sides

∴ x = 3

∴ The domain of the function is all real number greater than 3

* The domain is {x I x > 3}

∵ x can not be 3

∴ There is a vertical asymptote, its equation is x = 3

* The equation of the asymptote is x = 3

# Look to the attached graph for more understand for the domain

and the equation of the asymptote

4 0

3 years ago

What is the relative frequency of adults with tickets? Round to the nearest hundredth, if needed. 0.34 0.46 0.63 0.74 A two way

ki77a [65]

The answer is .34 I did the test

7 0

3 years ago

Help I don’t understand at all

zloy xaker [14]

Answer:

$1)\ \ 4h^2-13h+6\\2)\ \ 7x^3y^2-x^2y+1\\3)\ \ -7n+2\\4)\ \ -8m+4$

Step-by-step explanation:

1.

Simplify the expression by combining like terms. Remember, like terms have the same variable part, to simplify these terms, one performs operations between the coefficients. Please note that a variable with an exponent is not the same as a variable without the exponent. A term with no variable part is referred to as a constant, constants are like terms.

$2h^2-7h+2h^2-h+6+4h-9h$

$(2h^2+2h^2)+(-7h-h+4h-9h)+(6)$

$4h^2-13h+6$

2.

Use a very similar method to solve this problem as used in the first. Please note that all of the rules mentioned in the first problem also apply to this problem; for that matter, the rules mentioned in the first problem generally apply to any pre-algebra problem.

$8x^3y^2-7x^2y+8x-4-x^3y^2+2x^2y+4x^2y-8x+5$

$(8x^3y^2-x^3y^2)+(-7x^2y+2x^2y+4x^2y)+(8x-8x)+(-4+5)$

$7x^3y^2-x^2y+1$

3.

Use the same rules as applied in the first problem. Also, keep the distributive property in mind. In simple terms, the distributive property states the following ( $a(b+c)=(a)(b)+(a)(c)=ab+ac$ ). Also note, a term raised to an exponent is equal to the term times itself the number of times the exponent indicates. In the event that the term raised to an exponent is a constant, one can simplify it. Apply these properties here,