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natta225 [31]
3 years ago
5

The assistant manager of a surf shop estimates that 65% of customers will make a purchase. Part A: How many customers should a s

alesperson expect until he finds a customer that makes a purchase? Part B: What is the probability that a salesperson helps 3 customers until he finds the first person to make a purchase?
Mathematics
1 answer:
Ivan3 years ago
3 0

Answer:

A) 2

B) 0.239

Step-by-step explanation:

Part A) Expected value of a binomial distribution is the number of trials times the probability of success.

X = np

Given X = 1 and p = 0.65:

1 = 0.65n

n = 1.54

Rounding up, a salesperson should expect 2 customers until he finds a customer that makes a purchase.

Part B) Use binomial probability.

P = nCr pʳ qⁿ⁻ʳ

where n is the number of trials,

r is the number of successes,

p is the probability of success,

and q is the probability of failure (1−p).

Given n = 3, r = 1, p = 0.65, q = 0.35.

P = ₃C₁ 0.65¹ 0.35³⁻¹

P ≈ 0.239

Or, using binompdf function in a calculator:

binompdf(n, p, r)

= binompdf(3, 0.65, 1)

≈ 0.239

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The probability that exactly six out of ten carry a smartphone when travelling is; <u><em>P(6) = 0.146</em></u>

The missing part of the question is;

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Calculate P(6)

  • This is a binomial <em>probability distribution</em> problem that has a general formula as; P(x) = ⁿCₓ × pˣ × q⁽ⁿ ⁻ ˣ⁾

Where;

p is probability of success

q is probability of failure

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In this question;

n = 10

p = 75% = 0.75

q = 1 - p

q = 1 - 0.75

q = 0.25

Since six passengers are randomly selected, then applying the formula earlier quoted, we have;

P(6) = ¹⁰C₆ × 0.75⁶ × 0.25⁽¹⁰ ⁻ ⁶⁾

P(6) = 0.146

Read more at; brainly.com/question/24239758

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