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iragen [17]
3 years ago
11

Expand and simplify

Mathematics
1 answer:
Murrr4er [49]3 years ago
7 0
A. 5(3p + 2) - 2(4p - 3)
    5(3p) + 5(2) - 2(4p) + 2(3)
    15p + 10 - 8p + 6
     15p - 8p + 10 + 6
      7p + 16

b. 4(2x + 3) - (x - 2)
    4(2x + 3) - 1(x - 2)
    4(2x) + 4(3) - 1(x) + 1(2)
    8x + 12 - x + 2
    8x - x + 12 + 2
    7x + 14

c. (x + 3)(x - 2)
    x(x - 2) + 3(x - 2)
    x(x) - x(2) + 3(x) - 3(2)
    x² - 2x + 3x - 6
    x² + x - 6

d. (x - 1)(x - 2)
    x(x - 2) - 1(x - 2)
    x(x) - x(2) - 1(x) + 1(2)
    x² - 2x - x + 2
    x² - 3x + 2

e. (x - 3)(x - 2)
    x(x - 2) - 3(x - 2)
    x(x) - x(2) - 3(x) + 3(2)
    x² - 2x - 3x + 6
    x² - 5x + 6

f. (2p + 3)(p - 2)
   2p(p - 2) + 3(p - 2)
   2p(p) - 2p(2) + 3(p) - 3(2)
   2p² - 4p + 3p - 6
   2p² - p - 6

g. (3t - 2)(2t + 3)
    3t(2t + 3) - 2(2t + 3)
    3t(2t) + 3t(3) - 2(2t) - 2(3)
    6t² + 9t - 4t - 6
    6t² + 5t - 6

h. (2x - 5)(3x - 2)
    2x(3x - 2) - 5(3x - 2)
    2x(3x) - 2x(2) - 5(3x) + 5(2)
    6x² - 4x - 15x + 10
    6x² - 19x + 10
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A rectangle is inscribed with its base on the x-axis and its upper corners on the parabola y = 5 − x 2 . What are the dimensions
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Answer:

A rectangle is inscribed with its base on the x-axis and its upper corners on the parabola

y=5−x^2. What are the dimensions of such a rectangle with the greatest possible area?

Width =

Height =

Width =√10 and Height = \frac{10}{4}

Step-by-step explanation:

Let the coordinates of the vertices of the rectangle which lie on the given parabola y = 5 - x² ........ (1)

are (h,k) and (-h,k).

Hence, the area of the rectangle will be (h + h) × k

Therefore, A = h²k ..... (2).

Now, from equation (1) we can write k = 5 - h² ....... (3)

So, from equation (2), we can write

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For, A to be greatest ,

\frac{dA}{dh} =0 = 10h-4h^{3}

⇒ h[10-4h^{2} ]=0

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⇒ h = ±\frac{\sqrt{10} }{2}

Therefore, from equation (3), k = 5 - h²

⇒ k=5-\frac{10}{4} =\frac{10}{4}

Hence,

Width = 2h =√10 and

Height = k =\frac{10}{4}.

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Which expression is equivalent to (StartFraction 4 m n Over m Superscript negative 2 Baseline n Superscript 6 Baseline EndFracti
Gennadij [26K]

Question

Which expression is equivalent to \frac{4mn}{m^{-2}n^6}. Assuming m \neq 0; n\neq 0

Answer:

\frac{4m^3}{n^5}

Step-by-step explanation:

Given

\frac{4mn}{m^{-2}n^6}

Required:

Simplify

To simplify this, we start by splitting each individual function

\frac{4mn}{m^{-2}n^6} = \frac{4m}{m^{-2}} * \frac{n}{n^6}

From laws of indices

\frac{a^x}{a^y} = a^{x-y}

SO, the above expression can also be expressed the same way

\frac{4m}{m^{-2}} * \frac{n}{n^6} = 4m^{1-(-2)} * n^{1-6}

\frac{4m}{m^{-2}} * \frac{n}{n^6} = 4m^{1+2)} * n^{1-6}

\frac{4m}{m^{-2}} * \frac{n}{n^6} = 4m^{3} * n^{-5}

From laws of indices,

a^{-x} = \frac{1}{a^x}

So,

\frac{4m}{m^{-2}} * \frac{n}{n^6} = 4m^{3} * \frac{1}{n^5}

\frac{4m}{m^{-2}} * \frac{n}{n^6} = \frac{4m^3}{n^5}

Hence, \frac{4mn}{m^{-2}n^6} is equivalent to \frac{4m^3}{n^5}

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