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umka21 [38]
4 years ago
7

I have 0 idea how to do this plz help

Mathematics
2 answers:
nasty-shy [4]4 years ago
7 0

Answer:

x = 11

Step-by-step explanation:

Because of Vertical Angle Theorem, the inner angle that shares a side with 92 is 88.

So you use 88+4x+8+3x+7=180 because all triangles equal 180.

Combine like terms and get 103+7x=180

Subtract 103 on both sides and get 7x=77

Divide by 7 and  x =11

So answer is x = 11

IgorLugansk [536]4 years ago
6 0

Answer:

x = 11

88°

40°

52°

Step-by-step explanation:

Angles on a straight line add up to 180

92 + ? = 180

∴ 180 - 92 = 88

Angles inside a triangle add up to 180

88 + (3x + 7) + (4x + 8) = 180

∴ 88 + (3x + 4x) + (8 + 7) = 180

∴ 103 + 7x = 180

∴ 7x = 180 - 103

∴ 7x = 77

∴ x = 11

3x + 7 =

3(11) + 7 =

33 + 7 = 40

4x + 8 =

4(11) + 8 =

44 + 8 = 52

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3 years ago
Beth read a total of 12 books over 7 months.
givi [52]

She has been with her book club for 49 months.

Step-by-step explanation:

Books read = 12 books

Time period = 7 months

Therefore,

12 books = 7 months

1 book = \frac{7}{12}\ months    

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Total time period = x

84 books = x months

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Keywords: Unit rates, multiplication

Learn more about multiplication at:

  • brainly.com/question/10699220
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3 years ago
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andrew11 [14]

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3 years ago
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The circle is centered at the point (-3,4) and has a radius of length 3. What is its equation?
solong [7]
C is the right answer
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9. Plot the points A (-2,3), B(2,-3), C(2,3) ,D(-2,3) join the points and find the distance between each point.
pav-90 [236]

Answer:

AB=7.21 unit

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CD=7.21 unit

AD= 6 unit

AC=4 unit

BD=4 unit

Step-by-step explanation:

Coordinates of A =(-2,3)

Coordinates of B = (2,-3)

Coordinates of C = (2,3)

Coordinates of D =(-2,-3)

Distance formula :d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

A=(x_1,y_1)=(-2,3)\\B=(x_2,y_2)=(2,-3)\\AB = \sqrt{(2+2)^2+(-3-3)^2}

AB=7.21 unit

B=(x_1,y_1)=(2,-3)\\C=(x_2,y_2)=(2,3)\\BC=\sqrt{(2-2)^2+(3+3)^2}

BC=6

C=(x_1,y_1)=(2,3)\\D=(x_2,y_2)=(-2,-3)\\CD=\sqrt{(-2-2)^2+(-3-3)^2}

CD=7.21

A=(x_1,y_1)=(-2,3)\\D=(x_2,y_2)=(-2,-3)\\AD=\sqrt{(-2+2)^2+(-3-3)^2}

AD=6

A=(x_1,y_1)=(-2,3)\\C=(x_2,y_2)=(2,3)

AC=\sqrt{(2+2)^2+(3-3)^2}

AC=4

B=(x_1,y_1)=(2,-3)\\D=(x_2,y_2)=(-2,-3)

BD=\sqrt{(-2-2)^2+(-3+3)^2}

BD=4

4 0
3 years ago
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