Hello!
We are told that n and m are parallel.
The angle that measures 105 degrees is supplementary with the alternate interior angle of the angle which measures (3x - 18) degrees. Supplementary angles add to equal 180 degrees, so we can make an equation by first finding the measure of the alternate interior angle.
180 - 105 = 75
The alternate interior angle measures 75 degrees, so we can set that equal to 3x - 18 to solve for x since alternate interior angles are congruent.
75 = 3x - 18
93 = 3x
31 = x
Answer:
x = 31
Answer:
<em>75</em>
Step-by-step explanation:
Given:
f(1) = 100
f(n+1) = f(n) - 5
Solve for:
f(6)
Solution:
f(1) = 100
f(2) = f(1) - 5 = 100 - 5 = 100 - 1 x 5 = f(1) - 1 x 5
f(3) = f(2) - 5 = 100 - 5 - 5 = 100 - 2 x 5 = f(1) - 2 x 5
...
f(n) = f(n - 1) - 5 = 100 - (n-1) x 5 = f(1) - (n-1) x 5
=> f(6) = f(1) - (6-1) x 5 = 100 - 5 x 5 = 100 - 25 = 75
Hope this helps!
Ans: (6,-13)
Rationale:
Simply take your pre-image (point before applying transformation) of point B (4,-5) and apply the transformation to each point. Therefore, (x,y) = (4+2,-5-8) = (6,-13)
Answer:
Whole, natural, integer, rational, real
Step-by-step explanation:
15/5 can be rewritten as 3.
<h3>Answer 1a :- </h3>
Here we can solve this question using<em> </em><em>Unitary</em><em> </em><em>Method</em><em> </em><em>.</em> As ;
→ In 17hrs the boat travels 452km
→ In 1hr the boat will travel 452km/17
→ In 9hrs the boat will travel 452/17km * 9 = 239.29km
<h3>Answer 1b:-</h3>
→ A car can travel 156km on 13L gasoline .
→ It will travel 1km on 13/156L of gasoline .
→ It will travel 480km on 13/156*480L = 40L of gasoline .
<h3>
Answer 2a :-</h3>
→ A boat can go 180 miles on 60L gasoline.
→ It will go 1mile in 60/180L of gasoline.
→ It will go 306 miles in 60/180*306L = 102L of gasoline .
<h3>Answer 2b :-</h3>
→ On 51L of gasoline a car can go 408km
→ On 1L of gasoline car will go 408/51 km
→ On 11L of gasoline it will go 408/51*11L = 88km
