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2 years ago

14

Find the orthogonal projection of f onto g. use the inner product in c[a, b] f, g = b f(x)g(x) dx

1 answer:

Anvisha [2.4K]2 years ago

5 0

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antiseptic1488 [7]

$\mathrm{Domain\:of\:}\:x^2+2x-15\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-\infty \:$

$\mathrm{Range\:of\:}x^2+2x-15:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)\ge \:-16\:\\ \:\mathrm{Interval\:Notation:}&\:[-16,\:\infty \:)\end{bmatrix}$

$\mathrm{Axis\:interception\:points\:of}\:x^2+2x-15:\quad \mathrm{X\:Intercepts}:\:\left(3,\:0\right),\:\left(-5,\:0\right),\:\mathrm{Y\:Intercepts}:\:\left(0,\:-15\right)$

$\mathrm{Vertex\:of}\:x^2+2x-15:\quad \mathrm{Minimum}\space\left(-1,\:-16\right)$

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3 years ago

Write a paragraph proof to prove that triangles BHD and FHC are congruent

Katena32 [7]

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Step-by-step explanation:

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2 years ago

Find an equation in point-slope form for the line having the slope m= -5 and containing the point (7,2).

Juli2301 [7.4K]

Answer:

y - 2 = - 5(x - 7)

Step-by-step explanation:

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

Here m = - 5 and (a, b) = (7, 2) , thus

y - 2 = - 5(x - 7) ← equation in point- slope form

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