Answer:
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<h2>Given</h2>
<h3>Line 1</h3>
<h3>Line 2</h3>
- Passing through the points (4, 3) and (5, - 3)
<h2>To find</h2>
- The value of k, if the lines are perpendicular
<h2>Solution</h2>
We know the perpendicular lines have opposite reciprocal slopes, that is the product of their slopes is - 1.
Find the slope of line 1 by converting the equation into slope-intercept from standard form:
<u><em>Info:</em></u>
- <em>standard form is ⇒ ax + by + c = 0, </em>
- <em>slope - intercept form is ⇒ y = mx + b, where m is the slope</em>
- 3x - ky + 7 = 0
- ky = 3x + 7
- y = (3/k)x + 7/k
Its slope is 3/k.
Find the slope of line 2, using the slope formula:
- m = (y₂ - y₁)/(x₂ - x₁) = (-3 - 3)/(5 - 4) = - 6/1 = - 6
We have both the slopes now. Find their product:
- (3/k)*(- 6) = - 1
- - 18/k = - 1
- k = 18
So when k is 18, the lines are perpendicular.
Answer:
The correct answer is option C. 3/5= 0.60
Step-by-step explanation:
It is given that,the Venn diagram shows sports played by 10 students.
event A = The student plays basketball.
event B = The student plays soccer
<u>To find P(A|B))</u>
P(A) = 6
P(B) = 5
P(A ∩ B) = 3
We have P(A|B) = P(A ∩ B)/P(B)
= 3/5
= 0.6
Therefore the correct answer is option C. 3/5= 0.60
a = 30
a = 16
-a² + 46a -480 = 0
(-a + 30) (a -16) = 0
(-a)(a) + (-a)(-16) + 30(a) + 30(-16) = 0
-a² + 16a + 30a -480 = 0
-a² + 46a - 480 = 0
(-a + 30) = 0 ; (a - 16) = 0
-a = -30 ; a = 16
a = 30
To check:
a = 30
-(30)² + 46(30) - 480 = 0
-900 + 1380 - 480 = 0
480 - 480 = 0
0 = 0
a = 16
-(16)² + 46(16) - 480 = 0
-256 + 736 - 480 = 0
480 - 480 = 0
0 = 0
The arc is called B) Circle
