<em>The</em><em> </em><em>value</em><em> </em><em>of</em><em> </em><em>X </em><em>is</em><em> </em><em>9</em><em>2</em><em>.</em>
<em>pl</em><em>ease</em><em> </em><em>see</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em><em> </em><em>for</em><em> </em><em>full</em><em> </em><em>solution</em>
<em>Hope</em><em> </em><em>it</em><em> </em><em>helps</em>
Answer:
16,6
Step-by-step explanation:
OK so I used the Sine Rule
(10÷Sin37) = (X÷Sin90) [Then cross multiply]
10Sin90 = XSin37
(10Sin90 ÷Sin37) = X = 16,62
Answer:
Given two events A and B of a sample set :-
P[A] = 0.20
P[not B]=0.40
![P[B/A]=0.25](https://tex.z-dn.net/?f=P%5BB%2FA%5D%3D0.25)
To find P[A or B]:
![P[A or B] = P[A] + P[B] - P[A \cap B]](https://tex.z-dn.net/?f=P%5BA%20or%20B%5D%20%3D%20P%5BA%5D%20%2B%20P%5BB%5D%20-%20P%5BA%20%5Ccap%20B%5D)
......[1]
Calculate for ![P[B]](https://tex.z-dn.net/?f=P%5BB%5D)
and ![P[A \cap B]](https://tex.z-dn.net/?f=P%5BA%20%5Ccap%20B%5D)
P[B] = 1- P[not B]
Substitute the value P[not B] we get;
P[B] = 1-0.40 = 0.60
![P[A \cap B] = P[B/A] \cdot P[A]](https://tex.z-dn.net/?f=P%5BA%20%5Ccap%20B%5D%20%3D%20P%5BB%2FA%5D%20%5Ccdot%20P%5BA%5D)
Substitute the given values we get;
![P[A \cap B] = 0.25 \cdot 0.20 = 0.05](https://tex.z-dn.net/?f=P%5BA%20%5Ccap%20B%5D%20%3D%200.25%20%5Ccdot%200.20%20%3D%200.05)
Then;
![P[A or B] = 0.20+0.60-0.05 = 0.80-0.05 =0.75](https://tex.z-dn.net/?f=P%5BA%20or%20B%5D%20%3D%200.20%2B0.60-0.05%20%3D%200.80-0.05%20%3D0.75)
Therefore, the value of P[A or B] is, 0.75.
Answer:
Step-by-step explanation:
<u>f(x) is positive in the interval:</u>
<u>g(x) is positive in the interval:</u>
<u>The intersection of the above intervals is:</u>
Correct choice is A
Answer:
5 yd
Step-by-step explanation:
Formula to find area of a square is a² where each side is a,
So, a²=25
or, a=√25
or, a=±5
since a side can't be negative, so a = 5 yd
Answered by GAUTHMATH
