Question

Twice a number plus three times a second number is twenty two. Three times the first number plus four times the second is thirty one. Find the numbers

Answer 1

2x+3y=22
3x+4y=31

8x+12y=88
-9x-12y=-93
x=5
y=4

5 and 4.

Answer 2

Answer:

The numbers are 5 and 4

Step-by-step explanation:

Let the first number be x

Let the second number be y

For the first equation

2x + 3y = 22

For the second equation

3x + 4y = 31

Multiply the first one by 3 and the second one by 2

That's

First equation

6x + 9y = 66

Second equation

6x + 8y = 62

Subtract the second equation from the first one

That's

6x - 6x + 9y - 8y = 66 - 62

y = 4

Substitute y = 4 into 2x + 3y = 22

That's

2x + 3(4) = 22

2x = 22 - 12

2x = 10

Divide both sides by 2

x = 5

Hope this helps you