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rusak2 [61]
3 years ago
9

If a bicycle cost $70.50 but it's on sale for 47% off how much is the discount what is the sale price

Mathematics
1 answer:
Kryger [21]3 years ago
7 0

first multiply the two terms together to find out how much money is being discounted

$70.50 x .47 = 33.135

now subtract that number from $70.50

$70.50 - 33.135 = $37.37

ANSWER: the discount is $33.14 & the sale price is $37.37
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Factor completely 2x2 + 28x + 96.
Evgesh-ka [11]

Hi Kiara


2x²+28x+96

First thing you need to find the common factor

So the common factor is 2

2(x+6)(x+8)

I hope that's help:0


Why 2 is the common factor ?

Because we were looking for a number that can divide all of them at the same time without decimal, so that's why :)



4 0
4 years ago
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jim uses 3 cups of peaches to yield 4 jars of peach jam 4 jars of jam. He also makes strawberry-peach jam. He uses equal amounts
Levart [38]
Jim will probably need 6 cups of strawberries to yeild 10 jars
3 0
3 years ago
What is 4 1/2 - 1 <br> 8/10= in Fractions
umka21 [38]

4\frac{1}{2} - 1\frac{8}{10} = \frac{9}{2}- \frac{9}{5} = \frac{27}{10}

ok done. Thank to me :>

3 0
3 years ago
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Given the sample mean = 21.15, sample standard deviation = 4.7152, and N = 40 for the low income group,Test the claim that the m
miskamm [114]

Answer:

Null hypothesis:

\mathtt{H_o : \mu = 21.21}

Alternative hypothesis

\mathtt{H_1 : \mu \geq 21.21}

t = -0.080

Decision Rule: To  reject the null hypothesis if t > 1.340 at t

Since t = -0.080, this implies that t < 1.340 that means the t statistics value did not fall into the rejection region. Hence, we fail to reject the null hypothesis at the level of significance 0.10

Conclusion: We conclude that there is insufficient evidence to support the claim that the mean nickel diameter drawn by children in the low-income group is greater than 21.21 mm.

Step-by-step explanation:

Given that:

the sample mean \overline x = 21.15

the standard deviation \sigma = 4.7512

sample size N = 40

The objective is to test the claim that the mean nickel diameter drawn by children in the low-income group is greater than 21.21 mm.

At the level of significance of 0.1

The null hypothesis and the alternative hypothesis for this study can be computed as follows:

Null hypothesis:

\mathtt{H_o : \mu = 21.21}

Alternative hypothesis

\mathtt{H_1 : \mu \geq 21.21}

This test signifies a one-tailed test since the alternative is greater than or equal to 21.21

The t-test statistics can be computed by using the formula:

t= \dfrac{\overline x - \mu  }{\dfrac{\sigma}{\sqrt{n}}}

t = \dfrac{21.15- 21.21  }{\dfrac{4.7152}{\sqrt{40}}}

t = \dfrac{-0.06  }{\dfrac{4.7152}{6.3246}}

t = -0.080

degree of freedom = n - 1

degree of freedom =  40 - 1

degree of freedom = 39

From the t statistical tables,

at the level of significance ∝ = 0.1 and degree of freedom df = 39, the critical value of \mathtt{{T_{39,0.10} = 1.304}}

Decision Rule: To  reject the null hypothesis if t > 1.340 at t

Since t = -0.080, this implies that t < 1.340 that means the t statistics value did not fall into the rejection region. Hence, we fail to reject the null hypothesis at the level of significance 0.10

Conclusion: We conclude that there is insufficient evidence to support the claim that the mean nickel diameter drawn by children in the low-income group is greater than 21.21 mm.

5 0
3 years ago
Simplify the expression :
Black_prince [1.1K]

Answer:

58 x + 33 p thus 1) is the Answer

Step-by-step explanation:

Simplify the following:

11 (3 p + 5 x) + 4 x - x

4 x - x = 3 x:

11 (3 p + 5 x) + 3 x

11 (3 p + 5 x) = 33 p + 55 x:

33 p + 55 x + 3 x

Grouping like terms, 33 p + 55 x + 3 x = (55 x + 3 x) + 33 p:

(55 x + 3 x) + 33 p

55 x + 3 x = 58 x:

Answer:  58 x + 33 p

4 0
3 years ago
Read 2 more answers
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