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Airida [17]
3 years ago
6

A basketball team played 45 games. they won 60% of them. how many did they win?

Mathematics
2 answers:
SVETLANKA909090 [29]3 years ago
5 0
The answer that I got was 27, hope it helps
Ugo [173]3 years ago
4 0
The basketball team won 27 games.
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75% of b is 12. what is b?
zloy xaker [14]

Answer:

16

Step-by-step explanation:

same explanation as last time accept its 3/4 into 4/3

8 0
2 years ago
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A circle has a circumference of 7,850 units. What is the radius of the circle?
ioda

Answer:1250 units

Step-by-step explanation:

circumference=7850

Radius=?

Radius=circumference ➗ (2xπ)

Radius=7850 ➗ (2 x 3.14)

Radius=7850 ➗ (6.28)

Radius=1250 units

8 0
3 years ago
Ten less than 5 times the value of a number is equal to 10 times the quantity of
grandymaker [24]

Answer:

52

Step-by-step explanation:

given that the number is a

The expression for Ten less than 5 times the value of a number is given by

5a - 10

10 times the quantity of  12 more than one-fourth of the number.

a/4 is one-fourth  of number

12 more than one-fourth of the number

a/4 + 12

expression for  10 times the quantity of  12 more than one-fourth of the number. is given by

10(a/4 + 12) = 10a/4 + 12*10 = 2.5a + 120

Given that the above two expression are equal

equating them we have

5a - 10 = 2.5a + 120

adding 10 both sides

=>5a - 10+ 10  = 2.5a + 120 + 10

=> 5a = 2.5a + 130

subtracting 2.5a from both sides

=> 5a - 2.5a = 2.5a + 130 - 2.5a

=> 2.5a = 130

dividing both side by 2.5

=> a = 130/2.5 = 52

Thus, value of a is 52

5 0
3 years ago
Suppose that a researcher is designing a survey to estimate the proportion of adults in your state who oppose a proposed law tha
irinina [24]

Answer:

n=\frac{0.5 (1-0.5)}{(\frac{0.02}{1.96})^2}= 2401

So without prior estimation for the population proportion, using a confidence level of 95% if we want a margin of error about 2% we need al least a sample size of 2401.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution  

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})  

Solution to the problem

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}} (a)  

If solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2} (b)  

The margin of error desired for this case is ME= \pm 0.02 equivalent to 2% points

For this case we need to assume a confidence level, let's assume 95%. And since we don't have prior estimation for the population proportion of interest the best value to do an approximation is \hat p =0.5

In order to find the critical value we need to take in count that we are finding the margin of error for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:  

z_{\alpha/2}=\pm 1.96  

Now we have all the values needed and if we replace into equation (b) we got:

n=\frac{0.5 (1-0.5)}{(\frac{0.02}{1.96})^2}= 2401

So without prior estimation for the population proportion, using a confidence level of 95% if we want a margin of error about 2% we need al least a sample size of 2401.

5 0
3 years ago
A drop in temperature of 9 degrees overnight
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Whats the question?
8 0
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