Let
x---------> length original square side
x1--------> length resulting rectangle
y1--------> wide resulting rectangle
A1--------> area resulting rectangle
we know that
x1=x+2
y1=x-2
A1=60 in²
60=(x+2)*(x-2)--------> 60=x²-2x+2x-4-------> 60=x²-4------> x²=64
x1=8
x2=-8
the solution is
x=8 in
<span>the area of the original square is 8*8-------> 64 in</span>²
the answer is 64 in²
Pretty sure the answer is 21v + 11. Hope this helps :)
Answer:
No
Step-by-step explanation:
