Question

List the members of these sets.

Answer 1

Answer with Step-by-step explanation:

a.$x^2=1$

$x=\sqrt{1}=\pm 1$

x is a real number

Therefore, the set={-1,1}

b.x is a positive integer less than 12

Therefore, the value of x are

1,2,3,4,5,6,7,8,9,10,11

Set={1,2,3,4,5,6,7,8,9,10,11}

c.x is a square of an integer and x<100

Therefore, the value of x can be

1,4,9,16,25,36,49,64,81

Set={1,4,9,16,25,36,49,64,81}

d.x is an integer such that $x^2=2$

$x=\pm\sqrt{2}$

But x is an integer

$\sqrt 2$ and $-\sqrt 2$ are not integers.

Therefore, there is no integer element which satisfied $x^2=2$

Set=Null set=$\phi$