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Zarrin [17]
3 years ago
12

What are the solutions to the nonlinear system of equations below?

Mathematics
1 answer:
Sonbull [250]3 years ago
5 0
Substitute y=4x to the second equation:

x^2 + (4x)^2 = 17
x^2 + 16x^2 = 17
17x^2 = 17
x^2 = 17/17
x^2 = 1
x = 1 and -1

When x=1, y=4(1) = 4
When x=-1, y=4(-1) = -4

Thus the solutions would be (1,4) and (-1,-4). That would correspond to D. and A.
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what is There are (26)3⋅ 20 bacteria in a sample. What is the total number of bacteria in the sample? (1 point) PLLS help
erastova [34]

Answer:

hi taxes was waa Bynum waa Hitachi waa hug

5 0
3 years ago
4 children want to share 10 submarine sandwiches so that everyone gets the same amount. How much can each child have?​
kifflom [539]

Answer:

Each kid will get 2.5 submarine sandwiches

Step-by-step explanation:

4 0
2 years ago
If fixed cost of 20 article is 500 and variable cost for each article is 40. Find the total cost function? Also ,find the total
Deffense [45]

Answer:

Cost function = 40a + 500

Cost of 90 articles = $4,100

Step-by-step explanation:

The fixed cost is $500 and it will.not change regardless of production level.

The Variable cost is $40 and increases by every additional unit produced.

Assume the number of articles produced is a.

Cost function would be:

Total cost = Variable cost * Number of articles + Fixed cost

TC = 40a + 500

Using this, the cost of 90 articles is:

= 40 * 90 + 500

= $4,100

6 0
3 years ago
Does anyone know the answer to this??
Reptile [31]
The first answer and the last one

Plug in each number into their designated spots.
Example with (0,5)

0 goes into x and 5 goes into the y variable and this is the equation now:

2*0 +4*5=20

0 times 2 = 0 and 4*5=20
So that is one of the correct answers.

Repeat the process and you find that the last option is also correct.
7 0
3 years ago
5. A yacht is cruising at 20 knots at bearing of 185° when a 15 knot wind starts to blow at a bearing of 290°. Find the directio
kicyunya [14]

Answer:

<em>Direction of the boat is 43.05° and the speed is 21.66 knot</em>

<em></em>

Step-by-step explanation:

yacht speed = 20 knots

yacht bearing = 185° = 85°  below the negative horizontal x-axis

wind speed = 15 knots

wind bearing = 290° = 20° above the negative horizontal x-axis

we find the x and y components of the boat velocities

for yacht,

x component = -20 cos 85° = -1.74 knots

y component = -20 sin 85° = -19.92 knots

for the wind,

x component = -15 cos 20° = -14.09 knots

y component = 15 sin 20° = 5.13 knots

total x component  Vx = -1.74 + (-14.09) = -15.83 knots

total y component Vy =  -19.92 + 5.13 = -14.79 knots

Resultant speed of the boat = \sqrt{Vx^{2} + Vy^{2}  }

==> \sqrt{15.83^{2} + 14.79^{2}  } = <em>21.66 knot</em>

<em></em>

direction of boat = tan^{-1} \frac{Vy}{Vx}

==> tan^{-1} \frac{14.79}{15.83} = <em>43.05°</em>

3 0
3 years ago
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