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3 years ago

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The cost of tuition at Johnson Community College is $160 per credit hour. Each student also has to pay $50 in fees. Model the co

st,
C, for x credit hours taken.

1 answer:

cestrela7 [59]3 years ago

7 0

Answer:

C = 160x + 50

Step-by-step explanation:

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Find the equation of a line passing through (3, -5) that is parallel to 2x+6y=10

Zina [86]

Answer:

The equation of the line would be y = -1/3x - 4

Step-by-step explanation:

In order to find this, we first need to find the slope of the original line. We do this by solving for y.

2x + 6y = 10

6y = -2x + 10

y = -1/3x + 5/3

Now that we see the slope as -1/3, we know the new line will have the same slope thanks to the definition of parallel lines. So, we can use this slope and the point in point-slope form to find the equation.

y - y1 = m(x - x1)

y - -5 = -1/3(x - 3)

y + 5 = -1/3x + 1

y = -1/3x - 4

4 0

3 years ago

What Is The Surface Area Of this triangular prism? The Base Of Each Triangle 42m And the height of the triangular base is 20m. (

ehidna [41]

Answer:

The surface area is $2,440\ m^{2}$

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

The surface area of a triangular prism is equal to

$SA=2B+PH$

where

B is the area of the triangular base

P is the perimeter of the triangular face

H is the height of the prism

<em>Find the area of the base B</em>

$B=\frac{1}{2}(42)(20)=420\ m^{2}$

<em>Find the perimeter of the base P</em>

$P=(42+29+29)=100\ m$

we have

$H=16\ m$

substitute the values

The surface area is

$SA=2(420)+100(16)=2,440\ m^{2}$

8 0

3 years ago

Help please thanks multiple choice..........

vlada-n [284]

The answer is 7 fifths

7 0

3 years ago

Two numbers that are the same distance from zero on a number line are called what?

tamaranim1 [39]

Those are called opposites

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3 years ago

Read 2 more answers

Triangle PQR is transformed to triangle P'Q'R'. Triangle PQR has vertices P(4, 0), Q(0, −4), and R(−8, −4). Triangle P'Q'R' has

Whitepunk [10]

Answer:

Please find attached the required plot accomplished with an online tool

Part A:

1/4

Part B:

P''(-1, 0), Q''(0, -1), and R''(2, -1)

Part C:

Triangle PQR is similar to triangle P''Q''R'' but they are not congruent

Step-by-step explanation:

Part A:

Triangle ΔPQR has vertices P(4, 0), Q(0, -4), R(-8, -4)

Triangle ΔP'Q'R' has vertices P'(1, 0), Q'(0, -1), R'(-2, -1)

The dimensions of the sides of the triangle are given by the relation;

$l = \sqrt{\left (y_{2}-y_{1} \right )^{2}+\left (x_{2}-x_{1} \right )^{2}}$

Where;

(x₁, y₁) and (x₂, y₂) are the coordinates on the ends of the segment

For segment PQ, we place (x₁, y₁) = (4, 0) and (x₂, y₂) = (0, -4);

By substitution into the length equation, we get;

The length of segment PQ = 4·√2

The length of segment PR = 4·√10

The length of segment RQ = 8

The length of segment P'Q' = √2

The length of segment P'R' = √10

The length of segment R'Q' = 2

Therefore, the scale factor of the dilation of ΔPQR to ΔP'Q'R' is 1/4

Part B:

Reflection of (x, y) across the y-axis gives;

(x, y) image after reflection across the y-axis = (-x, y)

The coordinates after reflection of P'(1, 0), Q'(0, -1), R'(-2, -1) across the y-axis is given as follows;

P'(1, 0) image after reflection across the y-axis = P''(-1, 0)

Q'(0, -1) image after reflection across the y-axis = Q''(0, -1)

R'(-2, -1) image after reflection across the y-axis = R''(2, -1)

Part C:

Triangle PQR is similar to triangle P''Q''R'' but they are not congruent as the dimensions of the sides of triangle PQR and P''Q''R'' are not the same.

6 0

3 years ago