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zzz [600]
3 years ago
14

Solve equation 7(10)^n=700

Mathematics
1 answer:
blondinia [14]3 years ago
8 0

Answer:

Step-by-step explanation:

So first you would divide 7 both sides

7(10)^n=700

/7           /7

10^n=100

now we have to think 10 to what power is 100

10^2=100

so therefore n=2

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Simeon has two lengths of rope. One piece is 72 metres long and the other is 90 metres long. He wants to cut both lengths of rop
allsm [11]

Answer:

<h2><u><em>18</em></u></h2>

Step-by-step explanation:

90=2×3×3×5

72=2×2×2×3×3

HCF of 90 and 72  =2×3×3=

18

6 0
2 years ago
Please answer all of them. I only have today...
san4es73 [151]
1. Yes, x=9 is a solution because 8x= 72, and 72 can be greater then and equal to 58.

2. 1 + 0.24j


3. 2 units

4. 25 students per classroom

Hope this helps!
4 0
3 years ago
Abdul used a probability simulator to roll a 6-sided number cube and flip a coin 100 times. The results are shown in the tables
Sergio039 [100]
Answer

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6 0
3 years ago
Consider the function below. (If an answer does not exist, enter DNE.) g(x) = 190 + 8x3 + x4 (a) Find the interval of increase.
galben [10]

Answer:

The interval of increase of g(x) is (-6,+\infty).

Step-by-step explanation:

The interval of increase occurs when first derivative of given function brings positive values. Let be g(x) = 190 + 8 \cdot x^{3} + x^{4}, the first derivative of the function is:

g'(x) = 24 \cdot x ^{2} + 4\cdot x^{3}

g'(x) = 4 \cdot x^{2}\cdot (6+x)

The following condition must be met to define the interval of increase:

4\cdot x^{2} \cdot (x+6) > 0

The first term is always position due to the quadratic form, the second one is a first order polynomial and it is known that positive value is a product of two positive or negative values. Then, the second form must satisfy this:

x + 6 > 0

The solution to this inequation is:

x > - 6

Now, the solution to this expression in interval notation is: (-6,+\infty)

3 0
3 years ago
Consider the equation
muminat

Answer:

A. a=10\\ \\b\neq -8

B. a=10\\ \\b= -8

Step-by-step explanation:

Consider the equation

2(5x-4) = ax + b

A. This equation has no solutions when the coefficients at x are the same and the free coefficients are not the same.

First, use distributive property:

2(5x-4)=2\cdot 5x-2\cdot 4=10x-8

So, the equation is

10x-8=ax+b

This equation has no solutions when

a=10\\ \\b\neq -8

B. The equation has infinitely many solutions when the coefficients at x are the same and the free coefficients are the same too.

So, the equation

10x-8=ax+b

has infinitely many solutions when

a=10\\ \\b= -8

In other cases, the equation has a unique solution

5 0
3 years ago
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