Answer:
shown below
explanation:
<em>first</em><em> </em><em>off</em><em>,</em><em> </em><em>you</em><em> </em><em>get</em><em> </em><em>the</em><em> </em><em>like</em><em> </em><em>terms</em><em> </em><em>which</em><em> </em><em>is</em><em> </em><em>1</em><em>0</em><em> </em><em>and</em><em> </em><em>1</em><em>3</em><em>4</em>
12x=134+10
12x=144
<em>then</em><em> </em><em>you</em><em> </em><em>simplify</em><em> </em><em>which</em><em> </em><em>will</em><em> </em><em>look</em><em> </em><em>like</em><em> </em><em>this</em><em>:</em>
12x. 144
___ = ___
12. 12
144÷12=12
so the answer is option c.12
<h2>
hope it helps!!</h2>
x^3-2x^2+9x-2
To solve this, arrange the terms in descending order by their exponents
We notice that the number of pages read is a function of the number of days:
If y is the # of pages read and x the # days, so the equation becomes:
y = m.x + b where m is the rate of reading or the slope and b a constant. How to calculate m? and later b
Note that we can rewrite the given as:
x| 0 | 2 | 5 | 7 |
-|------|-----|-----|------|
y| 57 | 99|162 |204 |
m= (y₂-y₁)/(x₂-x₁) = Rise/Run
m= (204-162)/(7-5) = (162-99)/(5-2) = (99-57)/(2-0) = 21
Then
m = 21 and the function y = 21.x +b
We notice in the table that when x = 0; y = 57, then
57 = 0.x + b that means b = 5 and the final equation is:
y = 21.x + 57
Answer:
2.)70
4.)451,17
Step-by-step explanation:
2.)
a1 = 8*5 = 40
a2 = ((20-8)*5)/2 = 30
aTotal = 40+30 = 70
4.)
a1 = 18*18 = 324
a2 = (πr²)/2 = 127,17
aTotal = 127,17 + 324 = 451,17
Answer:
Any [a,b] that does NOT include the x-value 3 in it.
Either an [a,b] entirely to the left of 3, or
an [a,b] entirely to the right of 3
Step-by-step explanation:
The intermediate value theorem requires for the function for which the intermediate value is calculated, to be continuous in a closed interval [a,b]. Therefore, for the graph of the function shown in your problem, the intermediate value theorem will apply as long as the interval [a,b] does NOT contain "3", which is the x-value where the function shows a discontinuity.
Then any [a,b] entirely to the left of 3 (that is any [a,b] where b < 3; or on the other hand any [a,b] completely to the right of 3 (that is any [a,b} where a > 3, will be fine for the intermediate value theorem to apply.