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mash [69]
3 years ago
6

What is the difference between start fraction 3 over 7 end fraction and Start Fraction 1 over 14 End Fraction?

Mathematics
2 answers:
sukhopar [10]3 years ago
8 0

Answer:

C

Step-by-step explanation:

Vinvika [58]3 years ago
3 0

Answer:

5/14 option number c...

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3) 18 + 9 + 19 x 19<br> I do not no how to do it
Degger [83]

Answer:

388

Step-by-step explanation:

  • 18+9+361
  • 27+361
  • 388
8 0
2 years ago
Read 2 more answers
Complete the statement. Round to the nearest hundredth if necessary
Bond [772]

Answer:

45.9

Step-by-step explanation:

Remember that the hundredths place value is the second number after the decimal point and to round that number has to be greater than five in order to round up.

1m=3.28084

3.28084\times14=45.93176

Hundredths place value = 3

Round:

3

=45.9

Hope this helps.

8 0
2 years ago
Someone please help me with this!
Sveta_85 [38]

5(14-2)^2/2

5( 12)^2/2

Do the exponent

5(12*12)/2

5(144)/2

144/2= 72

72*5= 360

Answer : 360

8 0
2 years ago
Solve the system using substitution method <br> 3x+y=6<br> 2x-4y=10
Andreyy89
\left\{\begin{array}{ccc}3x+y=6&|-3x\\2x-4y=10\end{array}\right\\\\\left\{\begin{array}{ccc}y=6-3x\\2x-4y=10\end{array}\right\\\\substitute\ y=6-3x\ to\ the\ second\ equation\\\\2x-4(6-3x)=10\\\\2x-4\cdot6-4\cdot(-3x)=10\\\\2x-24+12x=10\\\\14x-24=10\ \ \ |+24\\\\14x=34\ \ \ \ |:14\\\\x=\dfrac{34}{14}\to x=\dfrac{17}{7}\\\\substitute\ the\ value\ of\ x\ to\ first\ equation\\\\y=6-3\cdot\dfrac{17}{7}=6-\dfrac{51}{7}=\dfrac{42}{7}-\dfrac{51}{7}=-\dfrac{9}{7}

\boxed{\left\{\begin{array}{ccc}x=\dfrac{17}{7}\\\\y=-\dfrac{9}{7}\end{array}\right}
5 0
2 years ago
Read 2 more answers
I WILL GIVE AN EXTRA 50 POINTS TO WHOEVER GETS THESE 2 QUESTIONS RIGHT
nikdorinn [45]

Answer:

See below for answers and explanations

Step-by-step explanation:

<u>Problem 1:</u>

A standard deck of cards contains 52 cards, consisting of 13 spades. If you select only one randomly, the probability of that occurring would be 13/52 or 1/4. Since there are only 26 red cards in a standard deck, then the probability of selecting a red card would be 26/52 or 1/2. Because the two events are independent of each other, their probabilities are multiplied. Therefore, the probability of selecting a spade, and then replacing it in hopes of drawing a red card is (1/2)(1/4) = 1/8.

<u>Problem 2:</u>

We are selecting a spade and then another spade while NOT replacing the first spade (remember that these events are independent of each other also). This means that the total card count will change by picking up the second card. Therefore, the probability of selecting a spade, followed by another spade, is (13/52)(12/51) = 156/2652 = 1/17.

4 0
3 years ago
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