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3 years ago

What fraction of an hour is 50 minutes

Mathematics

2 answers:

Arlecino [84]3 years ago

7 0

Answer: 5/6

Step-by-step explanation:

All we need do is to try to change 50 minutes to hour.

Remember that 60 minutes make 1 hour , so we need to find 50 minutes out of 1 hour , that is 50 minutes out of 60 minutes. Which is 50/60. Therefore:

50 minutes is 50/60 fraction of an hour

50/ 60 is the same as 5/6 in reduced form

den301095 [7]3 years ago

7 0

Answer:

Step-by-step explanation:

1hour is 60minutes

= 50/60

= 5/6

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3.30 Survey response rate. Pew Research reported in 2012 that the typical response rate to their surveys is only 9%. If for a pa

Artist 52 [7]

Answer:

0% probability that at least 1,500 will agree to respond

Step-by-step explanation:

I am going to use the binomial approximation to the normal to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that $\mu = E(X)$ , $\sigma = \sqrt{V(X)}$ .

In this problem, we have that:

$n = 15000, p = 0.09$

$\mu = E(X) = np = 15000*0.09 = 1350$

$\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{15000*0.09*0.91} = 35.05$

What is the probability that at least 1,500 will agree to respond

This is 1 subtracted by the pvalue of Z when X = 1500-1 = 1499. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{1499 - 1350}{35.05}$

$Z = 4.25$

$Z = 4.25$ has a pvalue of 1.

1 - 1 = 0

0% probability that at least 1,500 will agree to respond

6 0

3 years ago

X= 5y + 7 2x + 4y = 0 Solve for substitution

algol13

Answer:

x=2 and y= -1

Step-by-step explanation:

substitute x value in equation 2

2(5y+7)+4y=0

10y+14+4y=0

14y = -14

y= -1

here,

x= 5(-1)+7

x= -5+7

x=2

8 0

2 years ago

Read 2 more answers

Help please and thank you!!!!!

beks73 [17]

Answer:

60000

Step-by-step explanation:

The mean is the average

Add all the salaries together

(30000+30000+40000+40000+40000+50000+190000)

420000

Then divide by the number of number

420000/7

60000

6 0

3 years ago

Part B

Artyom0805 [142]

Answer: The side length of the square-shaped park is 120 meters.

Here we know that:

Here we Ann has two plots of land, one square and other triangular.

We know that the triangular one has an area of 32,500 m^2

And we also know that the total area is equal to 76,600 m^2

Then the area of the square plot will be equal to the difference between the total area and the area of the triangular plot.

area of the square plot = 76,600 m^2 - 32,500 m^2

Now, also remember that for a square of side length x, the area is given by:

A = x^2

Replacing that in the above equation we get:

x^2 = 76,600 m^2 - 32,500 m^2

Now we want to solve this for x, the side length of the square-shaped park.

First, let's solve the difference in the right side:

x^2 = 44,100 m^2

Now we can apply the square root in both sides to get:

√x^2 = √(44,100 m^2)

x = 210 m

The side length of the square-shaped park is 120 meters.

Step-by-step explanation:

7 0

2 years ago

As a bowl of soup cools, the temperature of the soup is given by the twice-differentiable function H for 0<img src="https://tex.

Aleks04 [339]

The rate of change of temperature with time at a point in time is given by

the derivative of the function for the temperature of the soup.

The correct responses are;

a) H'(5) is approximately -2.6 degrees Celsius per minute.

b) Yes

c) The equation for the line tangent is y = -3.6·t + 90.8
The approximate value of C(5) is 72.8 °C

d) The rate of change of the temperature of the soup at t = 3 minutes is -3.6 degrees Celsius per minute.

Reasons:

a) From the data in the table, we have;

The approximate value of H'(5) is given by the average value of the rate of

change of the temperature with time between points, t = 3, and t = 8

Therefore;

$\displaystyle H'(5) = \mathbf{\frac{H(8) - H(3)}{8 - 3}}$

Which gives;

$\displaystyle H'(5) = \frac{80 - 67}{8 - 3} = \mathbf{2.6}$

Therefore, H'(5) = -2.6°C per minute

b) Given that the function is twice differentiable over the interval, 0 ≤ t ≤ 12, the function for the change in temperature is continuous in the interval 0 ≤ t ≤ 12

At t = 0, H(0) = 90 °C

At t = 12, H(12) = 58 °C

58 °C < 60 < 90 °C

Therefore, there exist a temperature, of 60 °C between 90° C and 58 °C

c) The given derivative of C is, $C'(t) = \mathbf{-3.6 \cdot e^{-0.05 \cdot t}}$

At t = 3, we have;

$The \ slope \ at \ t = 3 \ is \ C'(3) = -3.6 \cdot e^{-0.05 \times 3} \approx -3.1$

Therefore, we have;

y - 80 ≈ -3.1 × (x - 3)

The equation for the tangent is; y = -3.6 × (x - 3) + 80

y = -3.6·x + 10.8 + 80 = -3.6·x + 90.8

The equation for the tangent is; y = -3.6·x + 90.8

The value of C(5) is approximately, C(5) ≈ -3.6 × 5 + 90.8 = 72.8

C(5) ≈ 72.8°

d) Based on the the model above, the rate at which the temperature of the

soup is changing at t = 3 minutes is -3.6 degrees per minute.

Learn more about calculus and concepts here:

brainly.com/question/20336420

8 0

2 years ago