<h3>
1.Area of the parallelogram= 288 square units</h3><h3>
2.Area of the parallelogram=45 
</h3><h3>
3.Area of the trapezoid = 34 square in.</h3><h3>
4.Area of the trapezoid = 8 square ft</h3><h3>
5.Area of the rhombus= 27 square cm</h3><h3>
6.Area of the rhombus= 108 square in</h3><h3>
7.The area of the desktop is = 1200 square in</h3><h3>
8.The area of the rhombus is =84 
</h3><h3>
9.Area of the trapezoid = 240 square ft</h3>
Step-by-step explanation:
1.
Base =16 ft and Height = 18 ft
Area of the parallelogram = base × height
=16× 18 square units
= 288 square units
2.
Base = 9 m and height = 5 m
Area of the parallelogram = base × height
=(9×5) 
=45 
3 .
Height = 4 in and parallel sides are 12 in and 5 in
Area of the trapezoid =
square in.
= 34 square in.
4.
Height = 2 ft and parallel sides are 2 ft and 6 ft
Area of the trapezoid =
square ft
= 8 square ft
5.
Diagonals are 6 cm and 9 cm.
Area of the rhombus 
square cm
= 27 square cm
6. Diagonals are 12 in and 18 in
Area of the rhombus 
square in
= 108 square in
7. Given a desktop in the shape of a parallelogram has a base 30 in. and a height of 40 in
The area of the desktop is = (30 × 40 ) square in
= 1200 square in
8. Given , a rhombus has one diagonal that is 14 cm and other diagonal 12 cm.
The area of the rhombus =

=84 
9.Given , the base of trapezoid are 24 ft and 16 ft and height is 12 ft
Area of the trapezoid =
=
square ft
= 240 square ft
It is 6, because 84:6=14 and 36:6=6
The point slope form or the equation of a line is :
y - y1 = m(x - x1)
First find the slope between the two coordinates:
m = y2-y1/x2-x1
m = 0-4 / 2-(-6)
m = -4 / 8
m = - 1/2
Now create the point slope form / equation of a line:
y - 4 = - 1/2(x - (-6))
y - 4 = - 1/2(x + 6)
OR you can have
y - 0 = - 1/2(x - 2)
3m=2(4+t)
3m= 8+2t
3m-8=2t
(divide everything by 2)
3/2m-4=t
t=3/2m-4
Answer:
3x +5+2x+44+110+123+136=360
5x+418=360
c. l. t
5x=58
therefore X=11.5