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Tatiana [17]
3 years ago
15

Find the product. (3p+2)(5p-7)

Mathematics
2 answers:
ryzh [129]3 years ago
6 0
15p^2-11p-14 is the product
g100num [7]3 years ago
5 0
5p X -29p = - 10 this is your answer 
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If there are fractions, eliminate them using the right methods. Then gather x and y terms on one side, and the rest on the other side. Simplify.
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Customers arrivals at a checkout counter in a department store per hour have a Poisson distribution with parameter λ = 7. Calcul
IgorLugansk [536]

Answer:

(1)14.9% (2) 2.96% (3) 97.04%

Step-by-step explanation:

Formula for Poisson distribution: P(k) = \frac{\lambda^ke^{-k}}{k!} where k is a number of guests coming in at a particular hour period.

(1) We can substitute k = 7 and \lambda = 7 into the formula:

P(k=7) = \frac{7^7e^{-7}}{7!}

P(k=7) = \frac{823543*0.000911882}{5040} = 0.149 = 14.9\%

(2)To calculate the probability of maximum 2 customers, we can add up the probability of 0, 1, and 2 customers coming in at a random hours

P(k\leq2) = P(k=0)+P(k=1)+P(k=2)

P(k\leq2) = \frac{7^0e^{-7}}{0!} + \frac{7^1e^{-7}}{1!} + \frac{7^2e^{-7}}{2!}

P(k \leq 2) = \frac{0.000911882}{1} + \frac{7*0.000911882}{1} + \frac{49*0.000911882}{2}

P(k\leq2) = 0.000911882+0.006383174+0.022341108 \approx 0.0296=2.96\%

(3) The probability of having at least 3 customers arriving at a random hour would be the probability of having more than 2 customers, which is the invert of probability of having no more than 2 customers. Therefore:

P(k\geq 3) = P(k>2) = 1 - P(k\leq2) = 1 - 0.0296 = 0.9704 = 97.04\%

4 0
2 years ago
What is the domain of the function F(x) = 4 cos(2x+1)?
Veseljchak [2.6K]

Answer:

Domain: (-inf, inf)

Range: [-4,4]

6 0
3 years ago
How do you convert the decimal 0.24 to fraction in the simplest form
RideAnS [48]

Answer:

0.24---> 24/100 --->  6/25

Step-by-step explanation:

hope that helps

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1 year ago
Find the possible values for m<1
Anuta_ua [19.1K]
0.5 that would be half of one if one is greater than the variable M



I really hope this helped ... have a great day !
4 0
2 years ago
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