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Nastasia [14]
3 years ago
5

A circular fountain has a radius of 9.4 feet. Find it's diameter and circumference to the nearest tenth.

Mathematics
2 answers:
Ksivusya [100]3 years ago
8 0
Actually the circumference is 59.0619 but rounded to the nearest tenth it would be 59.1 not 59.0
Elina [12.6K]3 years ago
6 0
The diameter is 18.8 feet
I believe the circumference is 59.0 feet
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Select from the drop-down menu to correctly complete the statement.
Usimov [2.4K]

The true statement is that: if you cannot get from one term to the next by adding or multiplying by a constant value, the sequence is neither arithmetic nor geometric

<h3>How to determine the true statement</h3>

A progression can either be arithmetic, geometric or neither.

  • When the progression has a common difference (gotten by addition), then the progression is arithmetic
  • When the progression has a common ratio (gotten by multiplication), then the progression is geometric

If the above are not true, then the sequence is neither arithmetic nor geometric

Read more about sequence at:

brainly.com/question/6561461

6 0
2 years ago
What does a b and c mean in algebra 1
wolverine [178]

They are variables. They stand in for different numbers in a problem. for example) a=12


7 0
3 years ago
Find the value of the missing angle in this triangle show work on how you found the answer.
lara31 [8.8K]
30 degrees is the value of the missing angle. Since, this triangle is known as an Isosceles all angles are equal.
7 0
3 years ago
please help :{ brainliest if you can get it right and I need you to prove why your answer is correct, thanksss​
beks73 [17]

Answer:

The Value of a=\frac{15}{4}.

Step-by-step explanation:

We have Named the figure please find the attachment for your reference.

Given:

PR = y

QR = a

RS = b

PS = z

PQ = x

QS = 15

∠P = 90°

∠R = 90°

∠Q = 60°

∠S = 30°

We need to find the Value of 'a'.

Solution:

Now we know that:

In Δ PQS

∠P = 90°

∠S = 30°

Now we know that;

sin\ \theta = \frac{opposite\ side}{Hypotenuse}

sin \ S= \frac{PQ}{QS}

Substituting the given values we get;

sin\ 30\°=\frac{x}{15}

Now we know that;

sin\ 30\° = \frac12

So we can say that;

\frac{1}{2}=\frac{x}{15}\\\\x=\frac{15}{2}

Now In Triangle PQR.

∠R = 90°

∠Q = 60°

So we can say that;

Cos \theta = \frac{adjacent \ Side}{Hypotenuse}\\

Cos\ Q = \frac{QR}{PQ}

Substituting the given values we get;

cos 60\°= \frac{a}{x}

Now we know that;

cos 60\°= \frac12

x=\frac{15}{2}

So substituting the values we get;

\frac{1}{2}=\frac{a}{\frac{15}{2}}

By Using Cross Multiplication we get;

a= \frac{1}{2}\times\frac{15}{2}\\\\a=\frac{15}{4}

Hence The Value of a=\frac{15}{4}.

6 0
3 years ago
1. Solve and verify each of the following systems of linear equations.
kakasveta [241]
5x - 2y = -6 ⇒ 10x - 4y = -12
2x - 1y =  1 ⇒ <u>10x - 5y =    5</u>
                                  y = -17
                   5x - 2(-17) = -6
                       5x + 34 = -6
                       <u>      - 34 - 34</u>
                               <u>5x</u> = <u>-40</u>
                                5       5
                                 x = -8
                           (x, y) = (-8, -17)

2x + 3y = 432 ⇒ 10x + 15y = 2160
5x + 2y =   16 ⇒ <u>10x +   4y =     32</u>
                                     <u>11y</u> = <u>2128</u>
                                      11       11
                                         y = 193.4545455
          2x + 3(193.4545455) = 432
              2x + 580.3636364 = 432
              <u>     - 580.3636364  - 580.3636364</u>
                                       <u>2x</u> = <u>-148.3636364</u>
                                        2                2
                                         x = -74.1818182
                                   (x, y) = (-74.1818184, 193.4545455)
6 0
4 years ago
Read 2 more answers
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