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cestrela7 [59]
3 years ago
14

Need Help Please!!!!

Mathematics
1 answer:
denis-greek [22]3 years ago
4 0

Answer:

4ab and 3ab

Step-by-step explanation:

4<em>ab</em> and 3<em>ab</em> because they have the same variables <em>a</em> and <em>b</em>

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The university needs to transport 421 fans from the stadium parking lot to the football game. If a van holds 10 people, how many
Tasya [4]
421/10= 42.1 vans since you can’t bring a 0.1 van you’ll have to bring a whole extra van so 43 vans

answer: one person will be in the partially full van
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3 years ago
Choose the table that represents g(x) = 3⋅f(x) when f(x) = x − 1.
Nastasia [14]

\bf f(x)=x-1\qquad \qquad g(x)=3\cdot f(x)\implies g(x)=\underline{3(x-1)} \\\\[-0.35em] ~\dotfill\\\\ \begin{array}{ccll} x&g(x)\\ \cline{1-2} 1&0\\2&3\\3&6 \end{array}\qquad \qquad (\stackrel{x_1}{1}~,~\stackrel{y_1}{0})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{6})

\bf slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{6-0}{3-1}\implies \cfrac{6}{2}\implies 3 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-0=3(x-1)\implies y=\underline{3(x-1)}

7 0
3 years ago
Read 2 more answers
Solve the differential equation x^3y"'− 3x^2 y" 6xy'−6y = 0.
Anna [14]
<span>Equation at the end of step  1  :</span><span> (((x3)•y)-(((3x2•y6)•x)•y))-6y = 0 </span><span>Step  2  :</span><span>Step  3  :</span>Pulling out like terms :

<span> 3.1 </span>    Pull out like factors :

  <span> -3x3y7 + x3y - 6y</span>  =  <span> -y • (3x3y6 - x3 + 6)</span> 

Trying to factor a multi variable polynomial :

<span> 3.2 </span>   Factoring   <span> 3x3y6 - x3 + 6</span> 

Try to factor this multi-variable trinomial using trial and error<span> 

 </span>Factorization fails

<span>Equation at the end of step  3  :</span><span> -y • (3x3y6 - x3 + 6) = 0 </span><span>Step  4  :</span>Theory - Roots of a product :

<span> 4.1 </span>   A product of several terms equals zero.<span> 

 </span>When a product of two or more terms equals zero, then at least one of the terms must be zero.<span> 

 </span>We shall now solve each term = 0 separately<span> 

 </span>In other words, we are going to solve as many equations as there are terms in the product<span> 

 </span>Any solution of term = 0 solves product = 0 as well.

Solving a Single Variable Equation :

<span> 4.2 </span>     Solve  :    -y = 0<span> 

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3 0
3 years ago
If the numbers 25, 30 ,40, 48 are in proportion, Middle terms are.....
zubka84 [21]

Step-by-step explanation:

it is 5/6 ..............

3 0
2 years ago
Past experience has indicated that the breaking strength of yarn used in manufacturing drapery material is normally distributed
vlabodo [156]

Answer:

95% two-sided confidence interval on the true mean breaking strength is (94.8cm, 99.2cm)

Step-by-step explanation:

Our sample size is 11.

The first step to solve this problem is finding our degrees of freedom, that is, the sample size subtracted by 1. So

df = 11-1 = 10.

Then, we need to subtract one by the confidence level \alpha and divide by 2. So:

\frac{1-0.95}{2} = \frac{0.05}{2} = 0.025

Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 10 and 0.025 in the two-sided t-distribution table, we have T = 1.812

Now, we find the standard deviation of the sample. This is the division of the standard deviation by the square root of the sample size. So

s = \frac{4}{\sqrt{11}} = 1.2060

Now, we multiply T and s

M = Ts = 1.812*1.2060 = 2.19/tex]For the lower end of the interval, we subtract the sample mean by M. So the lower end of the interval here is[tex]L = 97 - 2.19 = 94.81 = 94.8cm

For the upper end of the interval, we add the sample mean and M. So the upper end of the interval here is

L = 97 + 2.19 = 99.19 = 99.2cm

So

95% two-sided confidence interval on the true mean breaking strength is (94.8cm, 99.2cm).

7 0
3 years ago
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