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adelina 88 [10]
3 years ago
11

Using a savings amount of $450, assume you deposited the total amount

Mathematics
1 answer:
ankoles [38]3 years ago
4 0

Answer:

<h2> 7.3%</h2>

Step-by-step explanation:

Using the formula for calculating the simple interest to get the rate of return;

Simple Interest = Principal * Rate * Time/100

Given Principal = $450,

Time (in years) = 1 year

Simple interest = $32.75

Rate (in %) =?

Substituting the given values in the given formula to get the rate;

32.75 = 450*1*R/100

450R = 3275

R = 3,275/450

R = 7.3%

The rate of return is  7.3%

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3/1 x 2 /58 what is it
olya-2409 [2.1K]

Answer:

the answer would be 21/5 or 4.5

Step-by-step explanation:

to solve this equation you would use the butterfly method

3/1 x 2/58

3x28=84 and 5x1=5

your fraction is going to be 84/5.

84 can be reduced to 21. so your <u>answer would be 21/5</u>. in the decimal form, it would be <u>4.5</u>

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2 years ago
Is The sum of two prime numbers always a prime number and why or why not
astra-53 [7]
Yes because two odds make a positive
7 0
3 years ago
$648 increased 2/3 itself equals what amount?
ladessa [460]

Answer:

1080

Step-by-step explanation:

648x2=1296÷3=432+648=1080

6 0
3 years ago
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In 2018, Mike Krzyewski and John Calipari topped the list of highest paid college basketball coaches (Sports Illustrated website
expeople1 [14]

From the data given, we estimate the population mean and population standard deviation. Then, we use this estimate to find a 95% confidence interval for the population variance and the population standard deviation.

Sample:

Salaries in millions of dollars: 2.2, 1.5, 0.5, 1.3, 2.4, 1.5, 2.7, 0.3, 2.0, 0.3

Question a:

The mean is the sum of all values divided by the number of values. So

\overline{x} = \frac{2.2 + 1.5 + 0.5 + 1.3 + 2.4 + 1.5 + 2.7 + 0.3 + 2.0 + 0.3}{10} = 1.42

The sample mean salary is of 1.42 million.

Question b:

The standard deviation is the square root of the difference squared between each value and the mean, divided by one less than the number of values.

So

s = \sqrt{\frac{(2.2-1.42)^2 + (1.5-1.42)^2 + (0.5-1.42)^2 + (1.3-1.42)^2 + (2.4-1.42)^2 + (1.5-1.42)^2 + (2.7-1.42)^2 + ...}{9}} = 0.8772

Thus, the estimate for the population standard deviation is of 0.8772 million.

Question c:

The sample size is n = 10

The significance level is \alpha = 1 - 0.05 = 0.95

The estimate, which is the sample standard deviation, is of s = 0.8772.

Now, we have to find the critical values for the Pearson distribution. They are:

\chi^2_{\frac{\alpha}{2},n-1} = \chi^2_{0.025,9} = 19.0228

\chi^2_{1-\frac{\alpha}{2},n-1} = \chi^2_{0.975,9} = 2.7004

The confidence interval for the population variance is:

\frac{(n-1)s^2}{\chi^2_{\frac{\alpha}{2},n-1}} < \sigma^2 < \frac{(n-1)s^2}{\chi^2_{1-\frac{\alpha}{2},n-1}}

\frac{9*0.8772^2}{19.0228} < \sigma^2 < \frac{9*0.8772^2}{2.7004}

0.3641 < \sigma^2 < 2.5646

Thus, the 95% confidence interval for the population variance is (0.3641, 2.5646)

Question d:

Standard deviation is the square root of variance, so:

\sqrt{0.3641} = 0.6034

\sqrt{2.5646} = 1.6014

The 95% confidence interval for the population standard deviation is (0.6034, 1.6014).

For more on confidence intervals for population mean/standard deviation, you can check brainly.com/question/13807706

4 0
3 years ago
I have a test tomorrow
Nana76 [90]

well i wish you the best of luck buddy

5 0
4 years ago
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