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Akimi4 [234]
3 years ago
5

3x + 2 3 y - 15 < 0 The point (x, 9) is a solution for the inequality shown. What is a possible value for x?

Mathematics
2 answers:
aalyn [17]3 years ago
6 0

Answer:

The answer is 2

Step-by-step explanation:


love history [14]3 years ago
4 0

Answer:

x is any number less than -64; i.e. -66

Step-by-step explanation:

Inequality

3x + 23y - 15 < 0

where point (x,9) satisfies this

Substitute 9 for y

3x + 23(9) - 15 < 0

3x + 207 - 15 < 0

3x + 192 < 0       Take away 192 from both sides

3x < -192             Divide both sides by 3 to isolate x

x < -64


Check:

3(-64) + 23(9) -15 < 0

-192 + 207 - 15 < 0

-192 + 192 < 0

Therefore x must be less that -64 to satisfy the point (x, 9) in this inequality.

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A and b are positive integers and a–b = 3. Evaluate the following: 125^(1/3a)/25^(1/2b)
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Value of \dfrac{125^{1/3a}}{25^{1/2b}} is  \dfrac{1}{125^{(\frac{1}{ab})}} .

<u>Step-by-step explanation:</u>

Here we have , a-b=3 . We need to evaluate : 125^(1/3a)/25^(1/2b) or ,

\dfrac{125^{1/3a}}{25^{1/2b}} . Let's find out:

⇒ \dfrac{125^{1/3a}}{25^{1/2b}}

⇒ \dfrac{5^3(^{1/3a})}{5^2(^{1/2b})}

⇒ \dfrac{5(^{3/3a})}{5(^{3/2b})}

⇒ 5^{(\frac{1}{a}-\frac{1}{b})} = 5^{(\frac{b-a}{ab})}

⇒ 5^{(\frac{-3}{ab})}

⇒ \dfrac{1}{125^{(\frac{1}{ab})}}

Therefore, Value of \dfrac{125^{1/3a}}{25^{1/2b}} is  \dfrac{1}{125^{(\frac{1}{ab})}} .

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