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3 years ago

Find BC if AC = 13 and AB = 10

Mathematics

1 answer:

maxonik [38]3 years ago

7 0

Answer:

BC=3

Step-by-step explanation:

We can solve this by eliminating given detail of A.

AC=13 , AB=10

To find BC, We minus AC With AB

BC= AC-AB

BC=3

3 Is the final answer

I hope this helps, dont hesitate to ask for any question.

Mark me as brainliest is appreciated.Tq!!

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Varvara68 [4.7K]

d is the answer' because it is :D

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3 years ago

What's the value of x and y?

krok68 [10]

Answer:

x = 45 and y = 90

Step-by-step explanation:

Let the third angle be z

z = 180 - 135 (Linear Pair)

z = 45

Since its an iscosceles triangle,

<z = <x (angles opposite to equal sides have equal angles)

<x = 45 degree

<z + <x + <y = 180

45 + 45+ <y = 180

90 + <y = 180

<y = 180 - 90

<y = 90

Therefore x = 45 and y = 90

Hope u understood please mark as brainliest

Thank You

6 0

2 years ago

Read 2 more answers

Isabella is comparing the values below. Which list shows the values in descending order? 7.42, 7 79%, V48

Afina-wow [57]

Answer:

778%, 7.42, and V48

Step-by-step explanation:

I think that is right

8 0

3 years ago

Let f(x) = x+2/x+6 f^-1(-6) =

GREYUIT [131]

We can explicitly find the inverse. If $f^{-1}(x)$ is the inverse of $f(x)$ , then

$f\left(f^{-1}(x)\right) = \dfrac{f^{-1}(x)+2}{f^{-1}(x)+6} = x$

Solve for the inverse :

$\dfrac{f^{-1}(x) + 2}{f^{-1}(x) + 6} = x$

$\dfrac{f^{-1}(x) + 6 - 4}{f^{-1}(x) + 6} = x$

$1 - \dfrac4{f^{-1}(x) + 6} = x$

$1 - x = \dfrac4{f^{-1}(x) + 6}$

$f^{-1}(x) + 6 = \dfrac4{1-x}$

$\implies f^{-1}(x) = \dfrac4{1-x} - 6$

Then when x = -6, we have

$f^{-1}(-6) = \dfrac4{1-(-6)} - 6 = \dfrac47-6 = \boxed{-\dfrac{38}7}$

Alternatively, we can first solve for x such that $f(x) = -6$ . Then taking the inverse of both sides, $x = f^{-1}(-6)$ . (The difference in this method is that we don't compute the inverse for all x.)

We have

$\dfrac{x+2}{x+6} = -6$

$x + 2 = -6 (x + 6)$

$x + 2 = -6x - 36$

$7x = -38$

$\implies x = \boxed{-\dfrac{38}7}$

8 0

2 years ago

Dakota runs a half-marathon every 6 weeks, and madison runs a half-marathon every 15 weeks. if they start now, in how many weeks

LuckyWell [14K]

Dakota runs every 6 weeks......so he runs at 6 weeks, 12 weeks, 18 weeks, 24 weeks, 30 weeks

Madison runs every 15 weeks...so she runs at 15 weeks, 30 weeks, 45 weeks

so they will both be running a half-marathon at 30 weeks <==

6 0

2 years ago