Answer:
The last part is not there
Step-by-step explanation:
Step-by-step explanation:
Total bars = 4 + 5 + 7 + 9 = 25
Probability of Reese bar = 7/25
Probability of milky way = 9/25
Answer:
23) option c
JL ≈ 9.3
25) option c
y ≈ 9.6
Step-by-step explanation:
<h3>25)</h3>
Given in the question that,
cos(21°) = 9 / y
y = 9/cos(21°)
y = 9.64
y ≈ 9.6(nearest tenth)
<h3>23)</h3>
Given in the question that the hypotenuse of right angle triangle = 12
To find,
height of the right angle triangle
angle k = 39°
so by using trigonometry identity
cos(39) = opp/hypo
cos(39) = JL / KL
JL = cos(39)(12)
JL = 9.32
JL ≈ 9.3
<h3 />
solving the equation
we get ![x=6+2i\,\,and\,\,x=6-2i](https://tex.z-dn.net/?f=x%3D6%2B2i%5C%2C%5C%2Cand%5C%2C%5C%2Cx%3D6-2i)
Step-by-step explanation:
Solve the equation:
![x^2-12x+40=0](https://tex.z-dn.net/?f=x%5E2-12x%2B40%3D0)
We can solve using quadratic Formula:
![x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-b%5Cpm%5Csqrt%7Bb%5E2-4ac%7D%7D%7B2a%7D)
a= 1, b = -12, c = 40
Putting values:
![x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\x=\frac{-(-12)\pm\sqrt{(-12)^2-4(1)(40)}}{2(1)}\\x=\frac{12\pm\sqrt{144-160}}{2}\\x=\frac{12\pm\sqrt{-16}}{2}\\We\,\,know\,\,\sqrt{-1}=i\\ x=\frac{12\pm4i}{2}\\ x=\frac{12+4i}{2}\,\,and\,\, x=\frac{12-4i}{2}\\ x=\frac{4(3+i)}{2}\,\,and\,\, x=\frac{4(3-i)}{2}\\x=2(3+i)\,\,and\,\,x=2(3-i)\\x=6+2i\,\,and\,\,x=6-2i](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-b%5Cpm%5Csqrt%7Bb%5E2-4ac%7D%7D%7B2a%7D%5C%5Cx%3D%5Cfrac%7B-%28-12%29%5Cpm%5Csqrt%7B%28-12%29%5E2-4%281%29%2840%29%7D%7D%7B2%281%29%7D%5C%5Cx%3D%5Cfrac%7B12%5Cpm%5Csqrt%7B144-160%7D%7D%7B2%7D%5C%5Cx%3D%5Cfrac%7B12%5Cpm%5Csqrt%7B-16%7D%7D%7B2%7D%5C%5CWe%5C%2C%5C%2Cknow%5C%2C%5C%2C%5Csqrt%7B-1%7D%3Di%5C%5C%20x%3D%5Cfrac%7B12%5Cpm4i%7D%7B2%7D%5C%5C%20x%3D%5Cfrac%7B12%2B4i%7D%7B2%7D%5C%2C%5C%2Cand%5C%2C%5C%2C%20x%3D%5Cfrac%7B12-4i%7D%7B2%7D%5C%5C%20x%3D%5Cfrac%7B4%283%2Bi%29%7D%7B2%7D%5C%2C%5C%2Cand%5C%2C%5C%2C%20x%3D%5Cfrac%7B4%283-i%29%7D%7B2%7D%5C%5Cx%3D2%283%2Bi%29%5C%2C%5C%2Cand%5C%2C%5C%2Cx%3D2%283-i%29%5C%5Cx%3D6%2B2i%5C%2C%5C%2Cand%5C%2C%5C%2Cx%3D6-2i)
So, solving the equation
we get ![x=6+2i\,\,and\,\,x=6-2i](https://tex.z-dn.net/?f=x%3D6%2B2i%5C%2C%5C%2Cand%5C%2C%5C%2Cx%3D6-2i)
Keywords: Solving quadratic equation
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