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MArishka [77]
3 years ago
12

Compare the values of the 4s in the number 900441358

Mathematics
1 answer:
Ipatiy [6.2K]3 years ago
5 0

Answer:

The 4 on the right is 10 times larger than the 4 on the left.

Step-by-step explanation:

In order to find this, we turn every number in the term into a 0 except for the 4.

4 on the right: 900441358 = 000400000 = 40,000

4 on the left: 900441358 = 000040000 = 4,000

Now that we have these two numbers, we can divide one by the other to find the relationship.

40,000/4,000 = 10

Therefore, the right one is 10 times as large as the left one.

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Answer:

50% chance because (10)/(20)=1/2=0.5=50%

Step-by-step explanation:

hope this helps

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Rewrite 1 3/4 using twentieths
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The correct answer is 29/20
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Ben want to make pizza with salami He is going to make 3 pizza so he chops the salami into thirds
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Answer:

a) 1/3

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3 years ago
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A bag contains coins of rupees 2 Rupees 1 and 50 paise, in ratio of 1 is to 2 is to 4. if the total amount is rupees 72 find how
BabaBlast [244]

Answer:

<u>Final </u><u>answer </u><u>-</u>

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4 0
2 years ago
Americans receive an average of 20 Christmas cards each year. Suppose the number of Christmas cards is normally distributed with
soldier1979 [14.2K]

The distribution of X is X ~ N (20 , 6) and the probability that this American will receive no more than 24 Christmas cards this year is 0.7486.

<h3>Probability</h3>

a. Distribution

X ~ N (20 , 6)

b. P(x ≤24)

= P[(x - μ ) / σ  (24 - 20) / 6]

= P(z  ≤0.67)

=  0.74857

=0.7486

Hence:

Probability = 0.7486

c. P(21 < x < 26)

= P[(21 - 26)/ 6) < (x - μ  ) / σ   < (24 - 20) / 6) ]

= P(-0.83 < z < 0.67)

= P(z < 0.67) - P(z < -0.)

=  0.74857- 0.2033

= 0.54527

Hence:

Probability =0.54527

d. Using standard normal table ,

P(Z < z) = 66%

P(Z < 0.50) = 0.66

z = 0.50

Using z-score formula,

x = z×  σ +  μ

x = 0.50 × 6 + 20 = 23

23 Christmas cards

Therefore the distribution of X is X ~ N (20 , 6) and the probability that this American will receive no more than 24 Christmas cards this year is 0.7486.

Learn more about probability here:brainly.com/question/24756209

#SPJ1

8 0
2 years ago
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