If this is a parabolic motion equation, then it is a negative parabola, which looks like a hill (instead of a positive parabola that opens like a cup). Your equation would be h(t)= -16t^2 + 20t +3. That's the equation for an initial velocity of 20 ft/s thrown from an initial height of 3 ft. And the -16t^2 is the antiderivative of the gravitational pull. Anyway, if you're looking for the maximum height and you don't know calculus, then you have to complete the square to get this into vertex form. The vertex will be the highest point on the graph, which is consequently also the max height of the ball. When you do this, you get a vertex of (5/8, 9.25). The 9.25 is the max height of the ball.
<span>The correct option is "20" because
f(n)=<span>n2</span>−n
(−4)=(−4<span>)2</span>−(−4)
=16+4
=20</span>
The slope is 5/1. This is because it goes up 5 units and right one unit. This corresponds with the fact that slope is the rise/run on a line.
its X < 1 or x > 3
where every the point goes is where the graph goes is what I do
Answer:
Option A is correct.
Step-by-step explanation:
The formula used for finding the volume of right cone is:
Volume of Right cone = (1/3)π.r².h
We need to find altitude i.e h
Volume of cone=V = 8579 m^3
Radius=r = 16m
Altitude =h =?
Putting values,
8579 = (1/3) * 3.14 * (16)^2*h
8579 = 1/3 * 3.14 * 256 *h
8579 = 267.95 * h
=> h = 8579/267.95
h = 32.0 m
So, Altitude of right cone is 32.0 m
Option A is correct.
