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3 years ago

Construct a residual plot of the amount of money in a person’s bank account and their age that would indicate a linear model.

Mathematics

1 answer:

stepladder [879]3 years ago

3 0

Answer:

The regression line is not a good model because there is a pattern in the residual plot.

Step-by-step explanation:

Given is a residual plot for a data set

The residual plot shows scatter plot of x and y

The plotting of points show that there is not likely to be a linear trend of relation between the two variables. It is more likely to be parabolic or exponential.

Hence the regression line cannot be a good model as they do not approach 0.

Also there is not a pattern of linear trend.

D) The regression line is not a good model because there is a pattern in the residual plot.

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The sum of 3 consecutive number multiples of 6 is 162 find thesse numbers

MAXImum [283]

let the numbers are x , x+1 ,x+2

∴ 6 [ x + (x+1) +(x+2) ] = 162

∴ x + (x+1) + (x+2) = 162/6 = 27

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3 years ago

Adult female height is normally distributed with a mean of 65.3 inches and a standard deviation of 2.32 inches. a) If an adult f

emmasim [6.3K]

Answer:

0.0423 is the probability that the adult female has a height less than 61.3 inches.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 65.3 inches

Standard Deviation, σ = 2.32 inches

We are given that the distribution of adult female height is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

P(adult female has a height less than 61.3 inches)

$P( x < 61.3) = P( z < \displaystyle\frac{61.3 - 65.3}{2.32}) = P(z < -1.7241)$

Calculation the value from standard normal z table, we have,

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3 years ago

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Y_Kistochka [10]

Answer:

x

Step-by-step explanation:

Let's simplify the LHS so it can be equated to the RHS.

$\frac{x}{x^{2} -4x+4} - \frac{x}{x^{2} -3x+2}$

$\frac{x}{(x-2)^{2} } - \frac{x}{(x-1)(x-2)}$

$\frac{x(x-1)-x(x-2)}{(x-2)^{2}(x-1)}$

$\frac{x^{2} -x-x^{2}+2x }{(x-2)^{2}(x-1)}$

$\frac{x}{(x-2)^{2}(x-1)}$

Hence, the missing term in the numerator of the answer is x

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2 years ago