Question

In a right triangle,one angle measures x°, where sin x°=4/5. What is the cos (90°-x°) ?

Answer 1

Answer:

cos (90 - x) = sin x = 4/5

Step-by-step explanation:

cos(90 - x) = sin x

90 -x lies in the first quadrant, in the first quadrant all are positive.

Given : sin x = 4/5

cos(90 - x) = sinx

cos (90 - x) = sin x = 4/5

Hope this will helpful.

Thank you.

Answer 2

Given that : sin x = 4/5. Find cos(90 degrees - x degrees ) = ?
So,
sin x = 4/5 = altitude/hypotinues,
So,
base = sqrt[5^2-4^2] = 3,
So,
cos(90 degrees - x degrees ) = sin(x degree) = 4/5 >=======< ANSWER