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Answer:
Already stole herrrrrr ahahah
Step-by-step explanation:
Answer:
- MN = (21 -6√3)/37 ≈ 0.286694
- RK = (14√3 -12)/37 ≈ 0.331046
Step-by-step explanation:
In the attached figure, we have defined LM to be length x. Then the other lengths on side AC are ...
AM = LR = x/√3
RC = (2/√3)RK = (2/√3)(2/√3)x = 4/3x
Then the sum of lengths along AC is ...
AC = AM +ML +LR +RC
1 = x(1/√3 +1 +1/√3 +4/3) = x(7/3 +2/√3) = x(7√3 +6)/(3√3)
Then the value of x is ...

The resulting matrix of the row operation is given as follows:
![R = \left[\begin{array}{ccc}7&4.5&-6\\-6&-3&12\end{array}\right]](https://tex.z-dn.net/?f=R%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D7%264.5%26-6%5C%5C-6%26-3%2612%5Cend%7Barray%7D%5Cright%5D)
<h3>How to find the resulting matrix?</h3>
We apply the row operation on the original matrix, given as follows:
![A = \left[\begin{array}{ccc}4&3&0\\-6&-3&12\end{array}\right]](https://tex.z-dn.net/?f=A%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4%263%260%5C%5C-6%26-3%2612%5Cend%7Barray%7D%5Cright%5D)
The operation is given by:

That is, applying to each element, we have that:
Hence the resulting matrix is:
![R = \left[\begin{array}{ccc}7&4.5&-6\\-6&-3&12\end{array}\right]](https://tex.z-dn.net/?f=R%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D7%264.5%26-6%5C%5C-6%26-3%2612%5Cend%7Barray%7D%5Cright%5D)
More can be learned about matrix operations at brainly.com/question/1821869
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