Answer:
See Below.
Step-by-step explanation:
We are given that ΔAPB and ΔAQC are equilateral triangles.
And we want to prove that PC = BQ.
Since ΔAPB and ΔAQC are equilateral triangles, this means that:
Likewise:
Since they all measure 60°.
Note that ∠PAC is the addition of the angles ∠PAB and ∠BAC. So:
Likewise:
Since ∠QAC ≅ ∠PAB:
And by substitution:
Thus:
Then by SAS Congruence:
And by CPCTC:
9514 1404 393
Answer:
C. 2y = (2x-1)/4
Step-by-step explanation:
An equation is linear when the exponents of the variables are 1 and the sum of the exponents of the variables in any term is 1.
a) 3xy = 4 . . . . sum of exponents is 1+1=2
b) f(x) = 2/3(1 -x^2) . . . . exponent is 2
c) 2y = (2x -1)/4 . . . . all exponents are 1 (linear)
d) y = 3/(x+1) ⇒ xy +y = 3 . . . . sum of exponents is 1+1 = 2
Answer:
B
Step-by-step explanation:
The line is solid, so eliminate A and D.
Also, the line is shaded below, so this eliminates C.
Answer:
y=4x+10
Step-by-step explanation:
2y-8x-20=0
2y-8x=0+20
2y-8x=20
2y=8x+20
y=4x+10
Hope that will help!!
Well TBH, does 0 really equal 3. no that means that they are parallel, there is no point of intersection.
