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jeka94
3 years ago
13

Use the multiplication principle to tell the total number of three-card hands (permutations) that can be made with two aces

Mathematics
1 answer:
alina1380 [7]3 years ago
3 0
We are asked for the total or three card hands that can be made with two aces. The three-card hand should have two aces. We will use permutation in solving this problem and the solution is shown below:
nPr = n! /(n-r)!
n=3
r=2
3P2 = 3!/(3-2)!
3P2 = 6

The answer is 6.

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The domain is x. The range is y (or in this case F(x)).

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