We are asked for the total or three card hands that can be made with two aces. The three-card hand should have two aces. We will use permutation in solving this problem and the solution is shown below: nPr = n! /(n-r)! n=3 r=2 3P2 = 3!/(3-2)! 3P2 = 6
There are 8 total outcomes on what the coin will land on. If you look at the image, you'll see that there are 3 outcomes for the coin landing on 2 heads and 1 tail.
