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jeka94
3 years ago
13

Use the multiplication principle to tell the total number of three-card hands (permutations) that can be made with two aces

Mathematics
1 answer:
alina1380 [7]3 years ago
3 0
We are asked for the total or three card hands that can be made with two aces. The three-card hand should have two aces. We will use permutation in solving this problem and the solution is shown below:
nPr = n! /(n-r)!
n=3
r=2
3P2 = 3!/(3-2)!
3P2 = 6

The answer is 6.

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2 years ago
Can you answer this? <br> factorise 6p + 24q
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Step-by-step explanation:

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3 years ago
Determine whether the ordered pair (1, 1) is a solution of the inequality. y ≤ -3x+1
solong [7]

-------------------------------------------------------------------------------------------------------------

Answer:  \textsf{(1, 1) is NOT a solution of the inequality}

-------------------------------------------------------------------------------------------------------------

Given:  y \le-3x + 1

Find:  \textsf{Determine if (1, 1) is a solution of the inequality}

Solution:  In order to determine if (1, 1) is a solution we need to plug in 1 for the x values and 1 for the y values and see if the equation evaluated to true.

<u>Plug in the values</u>

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  • 1 \le-3(1) + 1

<u>Simplify</u>

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  • 1 \le-2

As we can see the expression states that 1 is less than or equal to -2 which is false therefore (1, 1) is NOT a solution of the inequality.

3 0
1 year ago
Solve the problem algebraically. Clearly define all variables, write an appropriate equation, and solve.
hichkok12 [17]

Answer:

Y=8 and X=21

Step-by-step explanation:

The key to solving word (story) problems is to learn how to translate words and phrases into concise, precise math expressions (variables and operations).  Make a table and add to it as you do problems:

      is              means           =

    more than                        +

      twice                              2*x

      sum                               +

      of                            usually means multiply

     ...

Assign variables.  Try to assign variables to the values the problem asks you to find.

In this problem, there are two variables.   Let x = one number;   y = other numbers

Translate:

 "One number is 5 more than twice the other number"    means

            x          =    5    +        2     *      y

 "sum of the two numbers is 29"     means

      x   +   y                    = 29

Now, the easy math.

Use the value for x from the first equation and substitute that into the second equation:

    (5 + 2y)      +     y       =  29

     5 + 3y = 29                    (collect terms)

           3y = 24                (subtract 5 from both sides)

             y = 8

Now, put that value of y into either equation to solve for x  (Which equation is easier??)

     x + 8 = 29

       x  = 21                 (subtract 8 from both sides)

Checking (very important):

 Is 21 really 5 more than 2(8)?

      21 = 5+16     ?

      21  =  21? yes

 Is  21 + 8 = 29  ?

        29 = 29? yes

p.s., learn the process, don't just get the right answer;  there will be lots of problems that are solved the same way!

3 0
1 year ago
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