3 years ago

Plz help it’s due tonight!!!

Mathematics

1 answer:

poizon [28]3 years ago

4 0

Answer:

T = N

Step-by-step explanation:

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Last year a construction worker had a gross income $ 29,700, of the which he contributed 7% to his 401(k) plain. If he got paid

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3 years ago

Last year, Susan had 10,000 to invest. She invested some of it in an account that paid 6%

katrin2010 [14]

Answer:

In the account that paid 6% Susan invest $\$6,000$

In the account that paid 5% Susan invest $\$4,000$

Step-by-step explanation:

we know that

The simple interest formula is equal to

$I=P(rt)$

where

I is the Final Interest Value

P is the Principal amount of money to be invested

r is the rate of interest

t is Number of Time Periods

Part a) account that paid 6% simple interest per year

in this problem we have

$t=1\ years\\ P=\$x\\r=0.06$

substitute in the formula above

$I1=x(0.06*1)$

$I1=0.06x$

Part b) account that paid 5% simple interest per year

in this problem we have

$t=1\ years\\ P=\$10,000-\$x\\r=0.05$

substitute in the formula above

$I2=(10,000-x)(0.05*1)$

$I2=500-0.05x$

we know that

$I1+I2=\$560$

substitute and solve for x

$0.06x+500-0.05x=560$

$0.01x=560-500$

$0.01x=60$

$x=\$6.000$

therefore

In the account that paid 6% Susan invest $\$6,000$

In the account that paid 5% Susan invest $\$4,000$

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3 years ago

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Lesechka [4]

15 = 2Y - 5
20 = 2Y
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