Answer: Actual overhead costs always enter the Work-in-Process account.
Explanation:
The work-in-process account is an account where the value of goods yet to be completely produced are recorded while the overhead cost is simply a business running cost, that is cost on expenses the business makes to keep functioning.
Overhead cost is not recorded in work-in-process account, rather it is recorded as business expenses.
Answer:
What is the amount of Supplies Expense that AllTech Corporation will recognize for the year?
$1050
Explanation:
Beggining of the year 1800
Purchased 1150
End of the year 1900
Expenses 1050
end = beg+purtcahse-expense
expense=beg+purchases-end
expense=1050
Answer:
e. $ 282,000
Explanation:
To determine the assets of the company at year end, we need to find the equity at year end, this is calculated as follows:
Opening Equity $ 145,000
Net Income for the year $ 45,000
Revenues $ 210,000
Expenses $ 165,000
Equity at end of year $ 190,000
The accounting equation is
Assets = Liabilities + Stockholders' Equity
Assets = $ 92,000 + $ 190,000 $ 282,000
Answer:
the probability that exactly 8 complete the program is 0.001025
Explanation:
given information:
60 % of those sent complete the program, p = 0.6
the total of people being sent, n = 27
exactly 8 complete the program, x = 8
to find the probability, we can use the following formula
![P(X=x)=\left[\begin{array}{ccc}n\\x\\\end{array}\right] p^{x} (1-p)^{n-x}](https://tex.z-dn.net/?f=P%28X%3Dx%29%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dn%5C%5Cx%5C%5C%5Cend%7Barray%7D%5Cright%5D%20p%5E%7Bx%7D%20%281-p%29%5E%7Bn-x%7D)
![P(X=8)=\left[\begin{array}{ccc}27\\8\\\end{array}\right] 0.6^{8} (1-0.6)^{27-8}](https://tex.z-dn.net/?f=P%28X%3D8%29%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D27%5C%5C8%5C%5C%5Cend%7Barray%7D%5Cright%5D%200.6%5E%7B8%7D%20%281-0.6%29%5E%7B27-8%7D)
![P(X=8)=\left[\begin{array}{ccc}27\\8\\\end{array}\right] 0.6^{8} (0.4)^{19}](https://tex.z-dn.net/?f=P%28X%3D8%29%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D27%5C%5C8%5C%5C%5Cend%7Barray%7D%5Cright%5D%200.6%5E%7B8%7D%20%280.4%29%5E%7B19%7D)
= 0.001025
