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pshichka [43]
3 years ago
10

I need help !!!

Mathematics
1 answer:
Xelga [282]3 years ago
7 0
It’s the second option
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Find the area of a circle with a circumference of \blueD{12.56}12.56start color #11accd, 12, point, 56, end color #11accd units.
mote1985 [20]

Answer:

12.55

Step-by-step explanation:

A = C²/4pi (3.14....) = 12.56² ÷ 4 × pi (3.14...) ≈ 12.556363, in this case we only take 12.55

6 0
3 years ago
Please help ASAP... another answer is D. Translation
STALIN [3.7K]

Answer:

B. Reflection

Step-by-step explanation:

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Help with the following attachment
GenaCL600 [577]

None of the answer choices makes any sense. (You should have your teacher show you how to select the correct choice.)

_____

Answers that are closer to the plotted points are ...

... A = -0.9, B = -9/16, C = -0.4, D = -1/16

The attachment shows these points plotted. As you can see, even these values aren't quite right.

3 0
3 years ago
6. There are six professors teaching the introductory dis- crete mathematics class at a university. The same final exam is given
podryga [215]

Complete question is;

There are six professors teaching the introductory discrete mathematics class at a university. The same final exam is given by all six professors. If the lowest possible score on the final is 0 and the highest possible score is 100.

How many students must there be to guarantee that there are two students with the same professor who earned the same final examination score?

Answer:

607 students

Step-by-step explanation:

To solve this question means we have to use Pigenhole principle which states that if y number of items are put into z number of containers, with y > z, then it means that that at least one container must definitely contain more than one item.

Now, let's find the number of boxes and objects:

If possible scores are from 0 to 100 with both inclusive it means number of possible scores = 101.

Now, If there was only one professor grading the students, in order to ensure that that there are two students with the same professor who earned the same final examination score,

The number of students would have to be = 101 + 1 = 102 students

Meanwhile, for each student, since there are 6 professors, the possible combination for a score will be = 6 possible combinations.

Therefore, number of students that will guarantee that there are two students with the same professor who earned the same final examination score must be a minimum of: (6 × 101) + 1 = 607

3 0
3 years ago
Simplify the Problem?
Pavel [41]

The answer is in the pictures.

6 0
3 years ago
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