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4vir4ik [10]
3 years ago
10

A triangle with area 45 square inches has a height that is two less than four times the width.

Mathematics
2 answers:
Art [367]3 years ago
7 0

Answer:

base=5

Height =18

olga2289 [7]3 years ago
5 0

Answer:base=5

Height =18

Step-by-step explanation:

18×5=90

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789,091 to the nearest ten thousand
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How do you find the missing variables in this problem please help
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Answer:

x = 55, y = 70, z = 125

Step-by-step explanation:

125 and x are adjacent angles and are supplementary, then

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4 0
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3 years ago
Factor the expression completely over the complex numbers. X3+5x2+9x+45
shepuryov [24]

x^3+5x^2+9x+45=x^2(x+5)+9(x+5)=(x+5)(x^2+9)=(*)\\\\x^2+9=x^2+3^2=x^2-(-1)(3^2)=x^2-(i^2)(3^2)=x^2-(3i)^2\\\\i=\sqrt{-1}\to i^2=-1\\\\(*)=(x+5)[x^2-(3i)^2]=(x+5)(x-3i)(x+3i)\\\\Used:\ a^2-b^2=(a-b)(a+b)\\\\Answer:\ x^3+5x^2+9x+45=(x+5)(x-3i)(x+3i)

4 0
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Please help me solve this challanging question 9 (step by step sulotion) 50 points!
defon

9514 1404 393

Answer:

  10

Step-by-step explanation:

Let L and T represent the initial amounts that Leo and Theo had. Let n represent the number of bills exchanged in the first exchange. Then we have ...

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After the second exchange, amounts trade places:

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Substituting this into the first equation, we get ...

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Leo gave Theo ten $20 bills.

_____

<em>Comment on the amounts</em>

Theo started with $600 more than Leo, including exactly 16 $50 bills. Leo had at least 10 $20 bills, so he could make the initial exchange. Whatever initial amount Leo had in excess of that $200 was matched in Theo's initial amount, but Theo must have had that excess in $20 bills only. For example, Leo may have started with $300 as 10×$20 +2×$50, but Theo's initial $900 would need to be 5×$20 +16×$50.

8 0
3 years ago
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