Equivalent fractions using the LCD 7/10 and 2/5
1 answer:
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Answer:
Step-by-step explanation:
Let f(x) be the polynomial function of minimum degree with real coefficients whose zeros are 5, -3, and -1 + 3i be f(x).
By the complex conjugate property of polynomials, -1-3i is also a root of this polynomial.
Therefore the polynomial in factored form is
We expand to get:
We expand further to get:\
Answer:
a) b) (a,b) (c, d) As long as (a,b) and (c,d) are the endpoints of of the diameter.
Step-by-step explanation:
a)
1) The reduced formula of the Circumference is given by:
2) Let's expand the factored one into one closer to the pattern above:
3) Completing the square for both trinomials:
4) In the Reduced Formula, ,
b) Using the previous example to show this:
When we factor this way
We are indeed, naming "a" and "b", the coordinates of (a, b) of the first endpoint and "b" and "d" the second endpoint as well.Id est, D (2, 5) and B (6,-11).
The radius, is
So yes, the equation of the circle can be written as
As long as (a,b) and (c,d) are the endpoints of of the diameter.
