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2 years ago

2x + y = 3 x = 2y - 1

1 answer:

8 0

2x+ y = 3
x = 2y - 1
Make sure there are NO SPACES in your answer. Include a comma in your answer.
It looks like I could substitute the x=2y-1. Into 2x+y=3
2(2y-1)+y=3
4y-2+y=3
5y=5
y=1
x=2(1)-1
x=1

(1,1)
CHECK
2x+y=3
2(1)+(1)=3
2+1=3
3=3
Left hand side=Right hand side
Check other equation
x=2y-1
1=2(1)-1
1=1
Therefore the solution is (1,1). Since the left hand side= right hand side in each equation

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Trina is looking at a scale drawing with a scale of 4 inches = 200 miles. how can she simplify the scale to evaluate 1 inch on t

vivado [14]

200/4 = 50

1 inch can be represented as 50 miles

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4 0

2 years ago

Ama's age is two thirds that of her elder sister. Four years ago ama's age was half the sister's. How old is the sister?

Westkost [7]

Answer:

Step-by-step explanation:

Ama's sister is 12 now and Ama is 8. 8/12 simplified is 2/3.

Four years ago Ama's would have been 4 and her sister would have been 8. 4/8 simplified is 1/2.

The equations:

(Ama is a)

(Ama's sister is s)

a = (2/3)s

a - 4 = (1/2)(s - 4)

Step one:

You would substitute the first equation into the second equation to get

(2/3)s - 4 = (1/2)(s - 4)

Step two:

Multiply by 6 to get rid of the fractions to get

4s - 24 = 3(s - 4)

Step three:

Simplify to get

4s - 24 = 3s - 12

Step four:

Subtract 3s and add 24 to get

s = 12

Step five:

Input the s value into the first equation to get

a = (2/3)(12) = 8

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8 0

2 years ago

Read 2 more answers

There are 158 students registered for American History classes. There are twice as many students registered in second period as

Margarita [4]

There are 28 students in first period and 56 students in sceond period and 74 students in third period

Solution:

Let the number of students in first period be "x"

Let the number of students in second period be "y"

Let the number of students in third period be "z"

There are 158 students registered for American History classes.

Therefore,

x + y + z = 158 ---------- eqn 1

There are twice as many students registered in second period as first period

number of students in second period = twice of number of students in first period

y = 2x ------- eqn 2

There are 10 less than three times as many students in third period as in first period

number of students in third period = 3 times number of students in first period - 10

z = 3x - 10 ------ eqn 3

Substitute eqn 2 and eqn 3 in eqn 1

x + 2x + 3x - 10 = 158

6x = 168

Substitute x = 28 in eqn 2

y = 2(28)

Substitute x = 28 in eqn 3

z = 3(28) - 10

z = 84 - 10

Thus there are 28 students in first period and 56 students in sceond period and 74 students in third period

5 0

2 years ago

C U12122 Write a Sum or Difference as a Product A 8 Questions 1. Use the GCF to rewrite the sum as a product. 30 + 16 a) 8 (3+2)

Alex73 [517]

Answer:

2(15+8)

Step-by-step explanation:

Given the expression 30+16

We are to use GCF to rewrite the sum as a product.

Get the factor of each value first as shown;

30 = 2 * 15

16 = 2 * 8

substitute the factors back into the expression:

30+16 = (2*15)+(2*8)

Since 2 is common to both terms, then:

30+16 = 2(15+8)

Hence the required sum of product of the terms is 2(15+8)

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2 years ago

I need help on this question

katen-ka-za [31]

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3 years ago