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Sedbober [7]
3 years ago
15

Becky buys 3 books and the total cost is $24.18. What is the constant of proportionality that relates the cost in dollars, y, to

the number of books, x?
Mathematics
1 answer:
disa [49]3 years ago
7 0

Answer: 1x = $8.06y

Step-by-step explanation:

thats honestly all i know..

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Can someone show me way of solving this​
erma4kov [3.2K]

Step-by-step explanation:

f(x) =  ln( \frac{1}{x} )

To find the derivative, notice we have a function 1/x inside of another function, ln(x)

We use what we call the chain rule,

It states that

derivative of a '

\frac{d}{dx} f(g(x)) =  f '(g(x)) \times \: g '(x)

Here f is ln(x)

f is 1/x

So first, we know that

\frac{d}{dx} ( ln(x)  =  \frac{1}{x}

so

f'(g(x)) =  \frac{1}{ \frac{1}{x} }

We know that

g'(x) =  - \frac{1}{ {x}^{2} }

So we have

x \times  -  \frac{1}{ {x}^{2} }  =   \frac{ - 1}{x}

4 0
1 year ago
Let v1,....., vk be vectors, and suppose that a point mass of m1,....., mk is located at the tip of each vector. The center of m
a_sh-v [17]

Answer: m1 = 4

m2 = 5

m3 = 2

Step-by-step explanation:

given (21/11, 6/11) = m1 (-1/3) + m2 (3, -2) + m3 (5, 2)

= (-m1 + 3m2 + 5m3) / 11 = 21/11

= (3m1 + (-2)m2 + 2m3) / 11 = 6/11

so that m1 + m2 +m3 = 11

-m1 + 3m2 + 5m3 = 21

3m1 - 2m2 + 2m3 = 6

from this, we get the augmented matrix as

\left[\begin{array}{cccc}-1&1&1&11\\-1&3&5&21\\3&-2&2&6\end{array}\right]

= \left[\begin{array{cccc}-1&1&1&11\\0&4&6&32\\0&-5&-1&-27\end{array}\right]  \left \{ {{R2=R2 + R1} \atop {R3=R3 -3R1 }]} \right.

= \left[\begin{array}{cccc}-1&1&1&11\\0&1&3/2&8\\0&-5&-1&-27\end{array}\right]

= \left[\begin{array}{cccc}-1&1&1&11\\0&1&3/2&8\\0&0&13/2&13\end{array}\right]

(R3 = R3 + 5R2)

this gives m1 + m2 + m3 = 11

m2 + 3/2 m3 = 8

13/2 m3 = 8

13/2 m3 = 13

m3 = 2

m2 = 8 -3/2 (2) = 5

= m1 = 11- 5 - 2 = 4

this gives

m1 = 4

m2 = 5

m3 = 2

4 0
3 years ago
Greatest to least: 2/5 2/3 6/10
myrzilka [38]

Answer:

Step-by-step explanation:

2/5 = 12/30

2/3 = 20/30

6/10 = 18/30

greatest to least : 2/3, 6/10, 2/5

7 0
3 years ago
Read 2 more answers
Please help me quick !!!
Nonamiya [84]

Answer:

subtract 0.4

Step-by-step explanation:

5 0
3 years ago
Help!!<br><br> which expression is equivalent to (m^5 n /pq^2) ^4
lana66690 [7]
\text{Use:}\\\\\left(\dfrac{a}{b}\right)^n=\dfrac{a^n}{b^n}\\\\(a\cdot b)^n=a^n\cdot b^n\\\\(a^n)^m=a^{nm}\\\\......................................................\\\\\left(\dfrac{m^5n}{pq^2}\right)^4=\dfrac{(m^5n)^4}{(pq^2)^4}=\dfrac{(m^5)^4n^4}{p^4(q^2)^4}=\dfrac{m^{20}n^4}{p^4q^8}
8 0
3 years ago
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