Answer:
Use demos it is reaaly helpful with this
29 cents..............................
Answer:
<h3>Hence required integers are 11 and 13</h3>
Let x an odd positive integer
Then, according to question
x^2 +(x+2)^2=290
2x^2 +4x−286=0
x^2 +2x−143=0
x ^2+13x−11x−143=0
(x+13)(x−11)=0
x=11 as x is positive
Hence required integers are 11 and 13
Step-by-step explanation:
Hope it is helpful....
√m/3 = 4
To remove the radical sign, square both sides.
(√m/3)² = 4²
m/3 = 16
To remove the denominator of 3, multiply both sides by 3.
3 (m/3) = 3(16)
m = 48
To check: Substitute m by its value.
√m/3 = 4
√48/3 = 4
√16 = 4
4 = 4
