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STALIN [3.7K]
2 years ago
14

Given A = {x | x < 1}, B = {x | x ≥ 5}, and C = {x | x = 5}, match the following items. 1. A B Ø 2. A C {x | x ≥ 5} 3. B C {x

| x < 1 or x ≥ 5} 4. A ∩ B {x | x = 5} 5. B ∩ C {x | x < 1 or x = 5}
Mathematics
1 answer:
ivann1987 [24]2 years ago
6 0

Answer:

The matching is shown below.

Step-by-step explanation:

The given sets are defined as

A = {x | x < 1}

It means all the values of x which are less than 1.

B = {x | x ≥ 5}

It means all the values of x which are greater than or equal to 5.

C = {x | x = 5}

It means all the value of x is 5.

Union of two sets contains all the elements of both sets.

Intersection of two sets contains only common elements of both sets.

The matching is shown below.

        Sets                              Correct value

1.     A ∪ B                         {x | x < 1 or x ≥ 5}

2. A ∪ C                         {x | x < 1 or x = 5}

3. B ∪ C                         {x | x ≥ 5}

4. A ∩ B                         Ø

5. B ∩ C                         {x | x = 5}

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Answer:

X= 1 AND 13

Step-by-step explanation:

x2+14x = -13

by completing the square method

you add the square of half the coefficient of b to both sides

which is (14/2)^2

x^2+14x+(7^2) = -13 +(7^2)

x^2 + 7^2 = -13 + 49

x^2 + 7^2 = 36

(x + 7)^2 = 36

find the square root of both sides

(x+7) = + or - 6

x=7-6 ; 1

or

x= 7+6 ; 13

8 0
2 years ago
Data collected at Toronto Pearson International Airport suggests that an exponential distribution with mean value 2725hours is a
Ivan

Answer:

a) What is the probability that the duration of a particular rainfall event at this location is at least 2 hours?

We want this probability"

P(X >2) = 1-P(X\leq 2) = 1-(1- e^{-0.367 *2})=e^{-0.367 *2}= 0.48

At most 3 hours?

P(X \leq 3) = F(3) = 1-e^{-0.367*3}= 1-0.333 =0.667

b) What is the probability that rainfall duration exceeds the mean value by more than 2 standard deviations?

P(X > 2.725 + 2*5.540) = P(X>13.62) = 1-P(X

What is the probability that it is less than the mean value by more than one standard deviation?

P(X

Step-by-step explanation:

Previous concepts

The exponential distribution is "the probability distribution of the time between events in a Poisson process (a process in which events occur continuously and independently at a constant average rate). It is a particular case of the gamma distribution". The probability density function is given by:

P(X=x)=\lambda e^{-\lambda x}

The cumulative distribution for this function is given by:

F(X) = 1- e^{-\lambda x}, x\ geq 0

We know the value for the mean on this case we have that :

mean = \frac{1}{\lambda}

\lambda = \frac{1}{Mean}= \frac{1}{2.725}=0.367

Solution to the problem

Part a

What is the probability that the duration of a particular rainfall event at this location is at least 2 hours?

We want this probability"

P(X >2) = 1-P(X\leq 2) = 1-(1- e^{-0.367 *2})=e^{-0.367 *2}= 0.48

At most 3 hours?

P(X \leq 3) = F(3) = 1-e^{-0.367*3}= 1-0.333 =0.667

Part b

What is the probability that rainfall duration exceeds the mean value by more than 2 standard deviations?

The variance for the esponential distribution is given by: Var(X) =\frac{1}{\lambda^2}

And the deviation would be:

Sd(X) = \frac{1}{\lambda}= \frac{1}{0.367}= 2.725

And the mean is given by Mean = 2.725

Two deviations correspond to 5.540, so we want this probability:

P(X > 2.725 + 2*5.540) = P(X>13.62) = 1-P(X

What is the probability that it is less than the mean value by more than one standard deviation?

For this case we want this probablity:

P(X

8 0
3 years ago
A = b and c = d, then a x c = b x d<br> what kind of reasong is used here
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A = b is given to us

Multiply both sides by c to get
a = b
a*c = b*c
The rule to multiply both sides by c is the multiplicative property of equality

Then on the right side, replace c with d. This replacement is possible due to the fact that c = d. This is using the substitution property.

So we go from
a*c = b*c
to this
a*c = b*d
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Answer:

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Step-by-step explanation:

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