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3 years ago

Solve the expression (w - z)²

Mathematics

1 answer:

Snowcat [4.5K]3 years ago

3 0

It will be (w-z) (w-z) hope this helps!

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Jared made 12 3/4 cups of snack mix for a party.His guests eat 2/3 of the mix.How manysnack mix did his guest eat?

Fantom [35]

Answer:

<h3>The number of snacks did Jared's guest eat is $12\frac{1}{12}$ </h3>

Step-by-step explanation:

Given that Jared made $12\frac{3}{4}$ cups of snack mix for a party.

Let x be the cups of snacks mix made by Jared.

Therefore $x=12\frac{3}{4}$

His guests eat $\frac{2}{3}$ of the mix.

Let y be the guest eated snacks mix

Therefore $y=\frac{2}{3}$

<h3>To find how many snack mix did his guest eat :</h3>

Let z be the number of snacks did Jared's guest eat

Therefore z=x-y

$z=12\frac{3}{4}-\frac{2}{3}$

$=\frac{51}{4}-\frac{2}{3}$

$=\frac{51(3)-2(4)}{4\times 3}$

$=\frac{153-8}{12}$

$=\frac{145}{12}$

$=12\frac{1}{12}$

Therefore $z=12\frac{1}{12}$

<h3>Therefore the number of snacks did Jared's guest eat is $12\frac{1}{12}$ </h3>

5 0

4 years ago

12.89503 ronded to the hundreths is

Tpy6a [65]

Answer:

12.90

Step-by-step explanation:

The hundredth is the second decimal place.

Basically we want to drop the numbers after the 9.

12.89 <u>5</u>03

Use the underlined decimal place, right after what you are rounding to, to determine if you round up or down.

For numbers 0-4, round down (keep the number). For numbers 5-9, round up (increase by 1).

We need to round up because 5 is in the range 5-9.

"Add" 1 to the hundredth decimal place and treat it like addition:

. 12.89

. 12.90

7 0

3 years ago

1. The diagonal of a quadrilateral

zalisa [80]

Consider the length of diagonal is 8.5 cm instead of 8.5 m because length of perpendiculars are in cm.

Given:

Length of the diagonal of a quadrilateral = 8.5 cm

Lengths of the perpendiculars dropped on it from the remaining opposite vertices are 3.5 cm and 4.5 cm.

To find:

The area of the quadrilateral.

Solution:

Diagonal divides the quadrilateral in 2 triangles. If diagonal is the base of both triangles then the lengths of the perpendiculars dropped on it from the remaining opposite vertices are heights of those triangles.

According to the question,

Triangle 1 : Base = 8.5 cm and Height = 3.5 cm

Triangle 2 : Base = 8.5 cm and Height = 4.5 cm

Area of a triangle is

$Area=\dfrac{1}{2}\times base \times height$

Using this formula, we get

$Area(\Delta 1)=\dfrac{1}{2}\times 8.5\times 3.5$

$Area(\Delta 1)=14.875$

and

$Area(\Delta 2)=\dfrac{1}{2}\times 8.5\times 4.5$

$Area(\Delta 2)=19.125$

Now, area of the quadrilateral is

$Area=Area(\Delta 1)+Area(\Delta 2)$

$Area=14.875+19.125$

$Area=34$

Therefore, the area of the quadrilateral is 34 cm².

6 0

2 years ago

Could someone please help me with this?

ella [17]

I'm not really sure, but I think the answer is D

7 0

3 years ago

Solve for x.<br>3 - |8x-6I = 3<br><br>x= or x=

Ket [755]

Answer:

¾ = x

Step-by-step explanation:

Since 3 - 0 gives us the 3, we do this:

$0 = -|8x - 6|$

0 = -8x + 6 >> Distributive Property

-6 - 6

___________

-6 = -8x

__ ___

-8 -8

¾ = x

I am joyous to assist you anytime.

7 0

3 years ago

Solve the expression (w - z)²​

Solve the expression (w - z)²