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Alexeev081 [22]
3 years ago
13

Mrs. Kelly creates a garden. She buys 15 flowers and 3 bushes for a total cost of $160.32. Each bush costs $11.50 more than each

flower. How much does each bush cost?
Mathematics
1 answer:
Brut [27]3 years ago
8 0

The cost of each bush is $ 18.49

<h3><u>Solution:</u></h3>

Let "f" be the cost of each flower

Let "b" be the cost of each bush

<em><u>Given that Mrs. Kelly buys 15 flowers and 3 bushes for a total cost of $160.32</u></em>

15 flowers x cost of each flower + 3 bushes x cost of each bush = 160.32

15 \times f + 3 \times b = 160.32

15f + 3b = 160.32  ----- eqn 1

<em><u>Each bush costs $11.50 more than each flower</u></em>

Cost of each bush = 11.50 + cost of each flower

b = 11.50 + f  ------ eqn 2

<u><em>Let us solve eqn 1 and eqn 2 to find values of "b" and "f"</em></u>

Substitute eqn 2 in eqn 1

15f + 3(11.50 + f) = 160.32

15f + 34.5 + 3f = 160.32

18f = 160.32 - 34.5

18f = 125.82

<h3>f = 6.99</h3>

Substitute f = 6.99 in eqn 2

b = 11.50 + 6.99 = 18.49

<h3>b = 18.49</h3>

Thus the cost of each bush is $ 18.49

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1) Solving the term (3x + 5)(2x - 3) using F.O.I.L we get \mathbf{6x^2+x-15}

2) solving the term (x + 2)(x - 13) using F.O.I.L we get \mathbf{x^2-11x-26}

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1) (3x + 5)(2x - 3). Solve using the F.O.I.L.

F.O.I.L stands for First, Outer Inner Last

We have (3x + 5)(2x - 3)

First: 3x(2x)

Outer: 3x(-3)

Inner: 5(2x)

Last: 5(-3)

Solving we get:

(3x + 5)(2x - 3)\\=3x(2x)+3x(-3)+5(2x)+5(-3)\\=6x^2-9x+10x-15\\=6x^2+x-15

So, solving the term (3x + 5)(2x - 3) using F.O.I.L we get \mathbf{6x^2+x-15}

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F.O.I.L stands for First, Outer Inner Last

We have (x + 2)(x -13)

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Solving we get:

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The square of binomial is: (a+b)^2=a^2+2ab+b^2

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The square of binomial used is: (a-b)^2=a^2-2ab+b^2

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